Answer:
x^2 + 8x - 65 = 0.
Step-by-step explanation:
In order to solve the side of the enlarged area of 81 square inches, we use the equation in solving the area of a square. Area = side^2.
the increase in side will be x, so (4+x)^2 = 81, x^2 + 4x + 4x + 16 = 81
x^2 + 8x + 16 - 81 = 0
x^2 + 8x - 65 = 0.
Hoped this helped mark Brainliest!
Answer:
(3 x + 2) (5 x - 4)
Step-by-step explanation:
Factor the following:
15 x^2 - 2 x - 8
Factor the quadratic 15 x^2 - 2 x - 8. The coefficient of x^2 is 15 and the constant term is -8. The product of 15 and -8 is -120. The factors of -120 which sum to -2 are 10 and -12. So 15 x^2 - 2 x - 8 = 15 x^2 - 12 x + 10 x - 8 = 5 x (3 x + 2) - 4 (3 x + 2):
5 x (3 x + 2) - 4 (3 x + 2)
Factor 3 x + 2 from 5 x (3 x + 2) - 4 (3 x + 2):
Answer: (3 x + 2) (5 x - 4)
Answer:
B is the answer.
Step-by-step explanation:
![x^{\frac{m}{n} } = \sqrt[n]{x^{m} }](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%20%3D%20%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%20%7D)
![\sqrt[4]{81^{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81%5E%7B5%7D%20%7D)
= 
Answer: The coordinates of point C after the dilation are (-2, 5)
Step-by-step explanation:
I guess that you want to find where the point C ends after the dilation.
Ok, if we have a point (x, y) and we do a dilation with a scale A around the point (a,b), then the dilated point will be:
(a + A*(x - a), b + A*(y - b))
In this case we have:
(a,b) = (2,1) and A = 3.
And the coordinates of point C, before being dilated, are: (1, 2)
Then the new location of the point C will be:
C' = (1 + 3*(1 - 2), 2 + 3*(2 - 1)) = (1 -3, 2 + 3) = (-2, 5)
