Answer:
we have P(x) = mx + 1
Step-by-step explanation:
Allow me to revise your question for a better understanding:
<em>The pressure at sea level is 1 atmosphere and increases at a constant rate as depth increases. When Sydney dives to a depth of 23 meters, the pressure around her is 3.3 point, 3 atmospheres. The pressure p in atmospheres is a function of x, the depth in meters.</em>
My answer:
Given:
At O meter the the pressure is 1 (0, 1)
At 23 meters the the pressure is 3.3 (23, 3.3)
From that, we can form a linear equation with the standard form:
P(x) = mx + b (1)
The slope of (1) is:
<=> P(x) = 0.1x + b
Substitute the point (0, 1) into (1) we have:
1 = 0.1*0 + b
<=> b = 1
So we have the equation of this line will be: P(x) = mx + 1
Answer:
The answer to your question is the height of the lamp is 18.2 ft
Step-by-step explanation:
Data
Street lamp shadow = 31.5 ft
Street sign height = 8 ft
Street sign shadow = 14 ft
Street lamp height = x
Process
1.- To find the height of the lamp use proportions. In this kind of problem, we do not look for the length, but the shadow.
Street lamp height/street lamp shadow = street sign height/street sign
shadow
Substitution
x / 31.5 = 8 / 14
Solve for x
x = (31.5)(8) / 14
Simplification
x = 254.4 / 14
Result
x = 18.2 ft
It has not been indicated whether the figure in the questions is a triangle or a quadrilateral. Irrespective of the shape, this can be solved. The two possible shapes and angles have been indicated in the attached image.
Now, from the information given we can infer that there is a line BD that cuts angle ABC in two parts: angle ABD and angle DBC
⇒ Angle ABC = Angle ABD + Angle DBC
Also, we know that angle ABC is 1 degree less than 3 times the angle ABD, and that angle DBC is 47 degree
Let angle ABD be x
⇒ Angle ABC = 3x-1
Also, Angle ABC = Angle ABD + Angle DBC
Substituting the values in the above equations
⇒ 3x-1 = x+47
⇒ 2x = 48
⇒ x = 24
So angle ABD = 24 degree, and angle ABC = 3(24)-1 = 71-1 = 71 degree
V=basearea times 1/3 times height
basearea=6<span>4π m2
hmm, they try to make it difficult
basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9
h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20
v=1/3*64pi*20=1280pi/3 m^3=1350.4
C
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Add all of the percents up and then divide by 3. You get 89.6%
