Answer:
The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B
Step-by-step explanation:
Given as :
The distance drove by Jack Duffy = d = 12,568 miles
The fixed costs totaled = $1,485.00
The variable cost totaled = $2,015.75
Let The cost per mile that Jack Duffy charge = $x cost per miles
Now, According to question
The totaled cost = The fixed costs + The variable cost
Or, The totaled cost = $1,485.00 + $2,015.75
I.e The totaled cost = $3500.75
Now,
The cost per mile that Jack Duffy charge = 
I.e x = 
∴ x = $0.278 per miles
So,The cost per mile that Jack Duffy charge = x = $0.278 per miles .
Hence,The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B Answer
Answer:
Step-by-step explanation:
Given the fraction 
Consider its numerator and factor it:
You cann not take the cube root from 
you can only take the cube root from 
, then the smallest whole number 
such that is a cube number is
When 
Answer:
x≥38 points
Step-by-step explanation:
Julio wants to break his school’s scoring record of 864 points during his 24-game basketball season. During the first 8 games of the season, he scored a total of 256 points. Which inequality can be used to find x, the number of points Julio must average per game during the rest of the season to break the record?
julio has a 24 game basketball season.
he has played 8, it means there are 16 more games to go
therefore=
he has scored 256 nts, wic means there are still 608 points to go .
864-256=608
x is the points he more score per every game.
16x=608
to break the records ,he must score an extra point 1
so 16x≥608
x≥38
2,000 and 200 are the values of the 2s in 42256
<span><span>(<span>sinx</span>−<span>tanx</span>)</span><span>(<span>cosx</span>−<span>cotx</span>)</span></span>
<span>=<span>(<span>sinx</span>−<span><span>sinx</span><span>cosx</span></span>)</span><span>(<span>cosx</span>−<span><span>cosx</span><span>sinx</span></span>)</span></span>
<span>=<span>sinx</span><span>(1−<span>1<span>cosx</span></span>)</span><span>cosx</span><span>(1−<span>1<span>sinx</span></span>)</span></span>
<span>=<span>sinx</span><span>(<span><span>cosx</span><span>cosx</span></span>−<span>1<span>cosx</span></span>)</span><span>cosx</span><span>(<span><span>sinx</span><span>sinx</span></span>−<span>1<span>sinx</span></span>)</span></span>
<span>=<span><span>sinx</span><span>cosx</span></span><span>(<span>cosx</span>−1)</span><span><span>cosx</span><span>sinx</span></span><span>(<span>sinx</span>−1)</span></span>
<span>=<span>(<span>cosx</span>−1)</span><span>(<span>sinx</span>−1<span>)</span></span></span>
