Answer:
<em>t=60</em>
Step-by-step explanation:
3/2t-16=4/3t-6
(subtract 4/3t from both sides)
3/2t-16-4/3t=-6
(add 16 to both sides)
3/2t-4/3t=-6+16
(simplify)
1/6t=10
(divide by 1/6 (or multiply by 6 on both sides)
t=60
Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
Answer:
A baseline score of 99% needs to be set.
Step-by-step explanation:
Since this is an example of a classification problem (the classes being whether somebody has been infected with a new virus or not), the ideal score to achieve in such a case is 100%. Hence, a baseline score of 99% should be set in order to get to 100% by outperforming it.
Because removable discontituity means that the limit of the function at that point has a finite value, and then you define the value of the function as that valu (the limit value).
An asymptote means that the limit of the function goes to positive or negative infinity.
You cannot meet both conditions, finite and infinity limit at the same time.
Answer:
H0 ; μ ≤ 4 pCi/L
Ha ; μ > 4 pCi/L
The null hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is less than or equal to the safe level of 4pCi/L
H0 ; μ ≤ 4 pCi/L
The alternative hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.
Ha ; μ > 4 pCi/L
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
The null hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is less than or equal to the safe level of 4pCi/L
H0 ; μ ≤ 4 pCi/L
The alternative hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.
Ha ; μ > 4 pCi/L
