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2 years ago

A full bag of dog food weighs 5 1 2 pounds. How much dog food do you have if there are 3 3 4 bags in the cupboard

Mathematics

2 answers:

Ulleksa [173]2 years ago

6 0

You would have 171,008 lbs. of dog food. Because 512 pounds times 334 bags equals 171,008lbs.

VladimirAG [237]2 years ago

4 0

Now, we know there are 3 and 3/4 bags in the cupboard, and each one of them weights 5 and 1/2 lbs, so the amount in the cupboard is just their product.

now, let's firstly convert the mixed fractions to "improper" and do the product after,

$\bf \stackrel{mixed}{5\frac{1}{2}}\implies \cfrac{5\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{11}{2}}
\\\\\\
\stackrel{mixed}{3\frac{3}{4}}\implies \cfrac{3\cdot 4+3}{2}\implies \stackrel{improper}{\cfrac{15}{4}}\\\\
-------------------------------\\\\
\cfrac{11}{2}\cdot \cfrac{15}{4}\implies \cfrac{165}{8}\implies \stackrel{lbs}{20\frac{5}{8}}$

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You receive an email asking you to forward it to four other people to ensure prosperity. Assuming the chain isn't broken, how ma

dolphi86 [110]

well if it asks you to send to 4 people and there are 8 generations which includes yours that mean

1 sent to 4 - 4 recived

4 send to 4 each = 16 recived + the 4 before = 20 (generation 2)

16 send to 4 = 64 + 20 = 84 (generation 3)

64 send to 4 = 256 + 84= 320 (g4)

256 send to 4 = 1024 + 320 = 1344 (g5)

1344 s t 4 = 5376 + 1344= 6730 (g6)

so on and so forth till generation 8

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1 year ago

Read 2 more answers

A. Find x. The figure is not drawn to scale.

blondinia [14]

Based on the given figure above, we can conclude that the triangle is an isosceles triangle. By definition, an isosceles triangle is a triangle that has at least two equal sides. Since this is an isosceles triangle, 8x-10 =6x. Now we can solve for x. So,
8x-10 =6x
8x-6x = 10
2x =10
x= 5.
Therefore, the value of x in the figure is 5. Hope this is the answer that you are looking for.

3 0

1 year ago

Consider a single spin of the spinner.

alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed. These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0

2 years ago

Read 2 more answers

The CEO of a local tech company wants to estimate the proportion of employees that are pleased with the cleanliness of the break

Zigmanuir [339]

Answer:

Methods of obtaining a sample of 600 employees from the 4,700 workforce:

Part A: The type of sampling method proposed by the CEO is Convenience Sampling.

Part B: When there are equal number of participants in both campuses, stratification by campus would give a more precise approximation of the proportion of employees who are satisfied with the cleanliness of the breakrooms than stratification by gender. Another method to ensure that stratification by campus gives a more precise approximation of the proportion of employees who are satisfied with the cleanliness of the breakrooms than stratification by gender is to ensure that the sample is proportional to the proportion of each campus to the whole population or workforce.

Step-by-step explanation:

A Convenience Sampling technique is a non-probability (non-random) sampling method and the participants are selected based on availability (early attendees). The early attendees might be different from the late attendees in characteristics such as age, sex, etc. Therefore, sampling biases are present. All non-probability sampling methods are prone to volunteer bias.

Stratified sampling is more accurate and representative of the population. It reduces sampling bias. The difficulty arises in choosing the characteristic to stratify by.

3 0

2 years ago

In △XYZ, m∠Z = 34, x = 61 cm, and z = 42 cm. Find m∠X. Round your answer to the nearest tenth of a degree.

Elza [17]

M∠X = 54.3°.

Using the Law of Sines, we have:
$\frac{\sin{Z}}{z}=\frac{\sin{X}}{x}
\\
\\\frac{\sin{34}}{42}=\frac{\sin{X}}{61}$

Cross multiplying gives us
61(sin 34) = 42(sin X)

Divide both sides by 42:
(61(sin 34))/42 = (42(sin X))/42
(61(sin 34))/42 = sin X

Take the inverse sine of both sides:
sin⁻¹((61(sin 34))/42) = sin⁻¹(sin X)
54.3 = X

8 0

2 years ago