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Alex73 [517]
1 year ago
12

A. Find x. The figure is not drawn to scale.

Mathematics
1 answer:
blondinia [14]1 year ago
3 0
Based on the given figure above, we can conclude that the triangle is an isosceles triangle. By definition, an isosceles triangle is a triangle that has at least two equal sides. Since this is an isosceles triangle, 8x-10 =6x. Now we can solve for x. So,
8x-10 =6x
8x-6x = 10
2x =10
x= 5.
Therefore, the value of x in the figure is 5. Hope this is the answer that you are looking for. 
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James has a desk job and would like to become more fit, so he purchases a tread walker and a standing desk which will allow him
Hitman42 [59]

Answer:

answer is

-0.245 \pm2.160(0.205)

Step-by-step explanation:

After working this way for 6 months he takes a simple random sample of 15 days. He records how long he walked that day (in hours) as recorded by his fitness watch as well as his billable hours for that day as recorded by a work app on his computer.

Slope is -0.245

Sample size  n = 15

Standard error is 0.205

Confidence level 95

Sognificance level is (100 - 95)% = 0.05

Degree of freedom is n -2 = 15 -2 = 13

Critical Value =2.16 = [using excel = TINV (0.05, 13)]

Marginal Error = Critical Value * standard error

= 2.16 * 0.205

= 0.4428

-0.245 \pm2.160(0.205)

8 0
2 years ago
Read 2 more answers
What is the present value of a $50,000 decreasing perpetuity beginning in one year if the discount rate is 7% and the payments d
Trava [24]

Answer:

Present Value = $1666666.67

Step-by-step explanation:

Present Value of a Growing Perpuity is calculated using the following formula

PV =D/(r - g)

Where D = Dividend

r = Discount Rate

g = Growth rate

D = $50,000

r = 7%

r = 7/100

r = 0.07

g = 4%

g = 4/100

g = 0.04

PV = D/(r-g)

Becomes

PV = $50,000/(0.07-0.04)

PV = $50,000/0.03

PV = $1,666,666.67

So the Present Value of the perpuity is $1,666,666.67

4 0
2 years ago
naveed makes 6.5litres of soup,correst to the nearest 0.5 litre he serves portions of his soup in 330ml cups correct to the near
Karolina [17]

Answer:

Number of Cups = 19

Step-by-step explanation:

Given

Size of Soup = 6.5 litres

SIze of cup = 330 ml

Required

Number of Cups.

First, it'll be assumed that the size of cups are uniform (the same).

The number of cups needed is calculated by dividing the size of soup by the size of the cup;

Number of Cup = Size of Soup/Size of Cup

Number of Cup = 6.5 litres/ 330 ml

<em>Convert units;</em>

<em>1 litres = 1000 ml</em>

<em>So,</em>

<em>6.5 litres = 6.5 * 1,000 ml</em>

<em>6.5 litres = 6,500 ml</em>

<em></em>

So,

Number of Cups = 6500 ml/330 ml

Number of Cups = 19.696969697

From the solution above, Naveed will definitely be able to serve 19 cups. The remaining fractional part won't fill a cup;

Hence, Number of Cups = 19

3 0
1 year ago
oint Q is plotted on the coordinate grid. Point P is at (40, −20). Point R is vertically above point Q. It is at the same distan
JulsSmile [24]

Answer:

The Awnser Is C

Step-by-step explanation:

Hope This Helps! Have A Great Day

8 0
1 year ago
Read 2 more answers
Approximate the area under the curve y = x² from x = 2 to x = 5 using a Right Endpoint approximation with 6 subdivisions.
Tanzania [10]

Answer:

\text{Area}\,=36.75

Step-by-step explanation:

Using right estimation point simply means to form a bunch of rectangles between the two limits, x =2 and x = 5. and add the areas of all those rectangles.

There must be 6 subdivisions between 2 and 5. so, to do that:

\Delta{x}=\dfrac{5-2}{6}=0.5

the length of each subdivision is 0.5 units. That also means that the 6 rectangles in between the limits will each have the base length of 0.5 units.

So the endpoints of each subdivision from 3 to 5 will be:

\begin{tabular}{|c|c|c|c|c|}3&3.5&4&4.5&5\\\end{tabular}

By <em>right </em>endpoint approx<em>, </em>we mean that the height of the rectangles will be determined by the right endpoint of each subdivision, that is, it must be equal to the function value of the first limit.

\begin{tabular}{|c|c|c|}subdivision&$x$&height($y=x^2$)&3 to 3.5&3.5&12.25&3.5 to 4&4&16&4 to 4.5&4.5&20.25&4.5 to 5&5&25\end

Note that we have used the right-end-point of the subdivision to determine the height the rectangles.

All that's left to do now is to simply calculate the areas of the each of the rectangles. And add them up.

the base of each of the rectangle is \Delta{x}=0.5

and the height is determined in the table above.

\text{Area}\,=(0.5\times12.25)+(0.5\times16)+(0.5\times20.25)+(0.5\times25)

\text{Area}\,=0.5(12.25+16+20.25+25)

\text{Area}\,=36.75

3 0
2 years ago
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