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Anarel [89]
2 years ago
7

the speed of a vehicle just before the brakes are applied can be estimated using the formula s= (28.75d)^1/2, where s is the spe

ed (in miles per hour) of the vehicle and d is the length (in feet) of the skid marks the vehicle leaves. How fast was a car traveling if it left skid marks 45 feet long? Round your answer to the nearest hundreth.
Mathematics
1 answer:
babymother [125]2 years ago
7 0

(28.75*45)^(1/2)

\sqrt{1293.75}

= 35.97

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Difference of 86.42 - 2.1.
densk [106]

Answer:

The first one

Step-by-step explanation:

The decimals line up when you subtract them

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1 year ago
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In a new card game, you start with a well-shuffled full deck and draw 3 cards without replacement. If you draw 3 hearts, you win
lyudmila [28]

Answer:

Expected pay winning $50= $0.585

Expected pay winning $25= $2.36

Expected pay for anything else= $-4.35

Expected returns=3.59

Expected value for one play= $(-1.41)

Do not play this game because you will lose $1.41

Step-by-step explanation:

Probability P(3 hearts) = (13/52)×(12/51)×(11/50) = 0.013

Probability P(3black)= (26/52)×(24/51)×(23/50) = 0.118

Probability P(drawing anything else)= 1 - 0.013 - 0.118= 0.869

Expected pay($50)= 0.013$(50-5)= $ 0.585

Expected pay($25)= 0.118(25-5)$ = $2.36

Expected pay for anything else= 0.869(0-5)$ =$(-4.347)

Expected value of one play=$ (0.585 + 2.353 -4.347) = -$1.41

c) Do not play the game.

6 0
1 year ago
Ralph is paid twice per month. His work offers a flexible-spending account to be used for medical expenses. This plan allows Ral
slava [35]
In this question, we're assuming Ralph had 0 in his saving funds to start with.

The glasses cost 1200 dollars.

There are 12 months in a year.

Each month, Ralph is given his check two times, that means that Ralph receives his check 2(12), or 24, times per year.

Divide 1200 (the cost of the glasses) by 24 (the amount of times Ralph is given his check)

1200 / 24
Divide both numerator and denominator by 12
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Ralph should have put 50 dollars per pay check to pay for the glasses.

A is your answer.

Have an awesome day! :)
6 0
2 years ago
Alannah has two lengths of ribbon.
ankoles [38]

Answer:

Longest possible length for each of the shorter lengths of ribbon is 9 cm because greatest common factor for both 36 and 45 is 9.

Step-by-step explanation:

Alannah has two ribbons one length is 36cm and other is 45cm.

It asked to find shorter length of ribbons that each cut into equal pieces with out no ribbon left over.

So, let's find greatest common factor for both 36 and 45.

Let's prime factor each number

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45= 3*3*5

So, GCF is product of common factors for both numbers.

GCF= 3*3 =9

So, longest possible length for each of the shorter lengths of ribbon is 9 cm.

Learn more about GCF in brainly.com/question/21612147.

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1 year ago
In Martian Poker, the game is played with 8 cards drawn from a 52 card deck.
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Step-by-step explanation:

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