Question

It is recommended that adults consume at least 1,000 mg of calcium every day. One ounce of whole milk contains about 25 mg of calcium, and one ounce of cheddar cheese contains 200 mg of calcium. If a person meets the recommendation by consuming x ounces of whole milk and y ounces of cheddar cheese, then 25x + 2007 2 1,000. Which choice give an amount of milk and cheese tha a person could consume to meet the recommendation?
A. 50 oz milk and 2 oz cheese
B. O oz milk and 4.5 oz cheese
C. 10 oz milk and 3 oz cheese
D. 39 oz milk and 0 oz cheese

Answer 1

Given:

It is recommended that adults consume at least 1,000 mg of calcium every day.

$25x+200y\geq 1000$

Step-by-step explanation:

Let, x be the quantity of milk in ounces and y be the quantity of cheddar cheese in ounces.

A person meets the recommendation, if

$25x+200y\geq 1000$

For option A,

Substitute x=50 and y=2 in the given inequality.

$25(50)+200(2)\geq 1000$

$1250+400\geq 1000$

$1650\geq 1000$

This statement is true. So, option A is correct.

Similarly,

For option B,

Substitute x=0 and y=4.5 in the given inequality.

$25(0)+200(4.5)\geq 1000$

$900\geq 1000$

This statement is false. So, option B is incorrect.

For option C,

Substitute x=10 and y=3 in the given inequality.

$25(10)+200(3)\geq 1000$

$850\geq 1000$

This statement is false. So, option C is incorrect.

For option D,

Substitute x=39 and y=0 in the given inequality.

$25(39)+200(0)\geq 1000$

$975\geq 1000$

This statement is false. So, option D is incorrect.

Therefore, the correct option is only A.