Answer:
The herbicide has no impact on fish
Step-by-step explanation:
Experimental research includes to divide the concerned group 'fishes' here into 'treatment' & 'control' group, to study impact of a treatment. Hypothesis test the statistical significance of propositions. Null hypothesis signifies no impact, alternate hypothesis signifies impact.
Let averages enzyme level of treatment & control be Xt & Xc
- Null Hypothesis [H0] : Xt = Xc, or Xt - Xc = 0
- Alternate Hypothesis [H1] : Xt ≠ Xc, or Xt - Xc ≠ 0
If hypothesis test suggests that there is no significant difference between treatment & control group enzyme level, so we reject H0 & accept H1. It implies that the herbicide has no significant impact on fishes enzymes.
Answer:
x= -5
Step-by-step explanation:
3(5x+10)+10=6x-(x+10)
15x+30+10=6x-x-10
15x+40=5x-10
15x-5x=-10-40
10x=-50
x=-5
Answer:what are you solving it by
Step-by-step explanation:
Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation
Calculate z-scores for the following random variable and determine their probabilities from standard tables.
x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088
x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912
x = 65 in
z = (65 - 68)/3 = -1
P(x) = 0.1587
x = 71:
z = (71-68)/3 = 1
P(x) = 0.8413
Part (a)
For x > 72 in, obtain
300 - 300*0.9088 = 27.36
Answer: 27
Part (b)
For x ≤ 64 in, obtain
300*0.0912 = 27.36
Answer: 27
Part (c)
For 65 ≤ x ≤ 71, obtain
300*(0.8413 - 0.1587) = 204.78
Answer: 204
Part (d)
For x = 68 in, obtain
z = 0
P(x) = 0.5
The number of students is
300*0.5 = 150
Answer: 150
Answer:
The answer is "$ 11,961.43"
Step-by-step explanation:
Given values:
P = $ 9500
r= 2.1 %
time (t)= 11 year
total quarterly year =4
Formula:

quarterly time = 


