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gavmur [86]
2 years ago
15

This figure shows circle O with chords PM and LN .

Mathematics
2 answers:
emmainna [20.7K]2 years ago
5 0
<span>A circle with two minor arcs equal in measure.
So LN=PM</span>
Mrac [35]2 years ago
5 0

Answer:

LN= 15

Step-by-step explanation:

LN=PM and PM=15 Therefore, LN is equal to 15. (I know this isn't a very good explanation but I  don't have time right now to explain and I just want to confirm that this is correct! ) If you have a question I might be able to answer later! :D

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Show a way to count from 170 to 410 using tens and hundreds. circle at least 1 benchmark number
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Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.

The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.

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1 year ago
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a certain triangle has a 30 degree angle and a 60 degree angle. which must be a true statement about the triangle
Oduvanchick [21]
The last angle is 90 degrees

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2 years ago
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Two sides of a triangle have lengths 12 m and 14 m. The angle between them is increasing at a rate of 2°/min. How fast is the le
Dvinal [7]

Answer:

1.692 m/min

Step-by-step explanation:

Let \theta be the angle between the two sides and x be the length of the third side. By cosine rule,

x^2 = 12^2+14^2-2\times12\times14\cos\theta = 340 - 336\cos\theta

x= \sqrt{340 - 336\cos\theta}

We differentiate x with respect to \theta by applying chain rule.

\dfrac{dx}{d\theta} = \dfrac{336\sin\theta}{2\sqrt{340 - 336\cos\theta}} = \dfrac{168\sin\theta}{\sqrt{340 - 336\cos\theta}}

Rate of change of \theta is 2

\dfrac{\theta}{dt} = 2

Rate of change of x is

\dfrac{dx}{dt} = \dfrac{dx}{d\theta}\times\dfrac{d\theta}{dt}

\dfrac{dx}{dt} = \dfrac{168\sin\theta}{\sqrt{340 - 336\cos\theta}} \times2=\dfrac{336\sin\theta}{\sqrt{340 - 336\cos\theta}}

At 60°,

\dfrac{dx}{dt} = \dfrac{336\sin60}{\sqrt{340 - 336\cos60}} = 1.692 \text{ m/min}

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1 year ago
Find the volume of the composite space figure to the nearest whole number.
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Figure 1:
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Answer:

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Step-by-step explanation:

In the picture attached, the drawn of the situation is shown

<u>Data</u>

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From definition:

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