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2 years ago

5

In the chemistry lab an experiment requires 500mL of one ingredient to be mixed with 1000mL of another.How many ounces is the so

lution?

1 answer:

inna [77]2 years ago

3 0

Answer:

50.72

Step-by-step explanation:

add the 500 and 1000 mL of the substances and then divide the volume value by 29.574 to get ounces

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The owners of Prim's Pizza are concerned that many of their customers are starting to purchase pizza from The Pizza Palace becau

AleksandrR [38]

Answer:

$(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953$

$(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047$

And the confidence interval for the difference is between:

$27.953 \leq \mu_1 -\mu_2 \leq 32.047$

Step-by-step explanation:

We have the following info given:

$\bar X_1 = 240$ sample mean for medium Pizzas from Prim's

$\bar X_2 = 210$ sample mean for medium Pizzas from Pizza Place

$s_1 =8.6$ sample deviation for Prim's

$s_2 =5.7$ sample deviation for Pizza Palca

$n_1 =n_2 = 100$ sample size selected for each case

The confidence interval for the difference of means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

And for the 95% confidence we need a significance level of $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ , the degrees of freedom are given by:

$df= n_1 +n_2 -2= 100+100-2 =98$

And the critical value would be

$t_{\alpha/2}= 1.984$

And replacing we got:

$(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953$

$(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047$

And the confidence interval for the difference is between:

$27.953 \leq \mu_1 -\mu_2 \leq 32.047$

8 0

2 years ago

A local library claims it has 2.73x103 books. If there are 42 people in the building, how many books per capita are there?

sveticcg [70]

Answer:

$Per\ Capita = 64$

Step-by-step explanation:

Given

$Books = 2.7 * 10^3$

$People = 42$

Required

Determine the per capita

The per capita is calculated by dividing number of books by people as follows;

$Per\ Capita = \frac{Books}{People}$

Substitute 2.7 * 10^3 for books and 42 for people

$Per\ Capita = \frac{2.7 * 10^3}{42}$

$Per\ Capita = 64$ (Approximated)

<em>Hence, the per capita is 64</em>

5 0

2 years ago

Solve the following quadratic equation using the quadratic formula and then choose the correct solution set. 6x2 - 7x + 2 = 0

gtnhenbr [62]

<span>6x^2 - 7x + 2 = 0
(3x-2)(2x-1) = 0

</span>3x-2 = 0
x = 2/3

2x-1=0
x=1/2

answer: x=1/2 and x =2/3

4 0

2 years ago

Read 2 more answers

A taut string of length 10 inches is plucked at the center. The vibration travels along the string at a constant rate of c inche

Mademuasel [1]

Answer:

The correct option is

$A. \ \dfrac{1}{c} \times \left | x - 5 \right | = 0.3$

Step-by-step explanation:

The parameters given are;

The length of the string = 10 inches

The speed or rate of travel of the wave = c inches per millisecond

The position on the string from the left-most end = x

The time duration of motion of the vibration to reach x= 0.3 milliseconds

The distance covered = Speed × Time = c×0.3

Given that the string is plucked at the middle, with the vibration travelling in both directions, the point after 0.3 millisecond is x where we have;

The location on the string where it is plucked = center of the string = 10/2 = 5 inches

Distance from point of the string being plucked (the center of the string) to the left-most end = 5 inches

Therefore, on the left side of the center of the string we have;

The distance from the location of the vibration x (measured from the left most end) to the center of the string = 5 - x = -(x -5)

On the right side of the center, the distance from x is -(5 - x) = x - 5

Therefore, the the equation that can be used to find the location of the vibration after 0.3 milliseconds is $\dfrac{1}{c} \times \left | x - 5 \right | = 0.3$ or $\left | x - 5 \right | = 0.3 \times c$ which gives the correct option as A

8 0

2 years ago

Two percent of the customers of a store buy cigars. Half of the customers who buy cigars buy beer. 25 percent who buy beer buy c

enyata [817]

Answer:

0.95

Step-by-step explanation:

The computation of the probability that a customer neither buys beer nor buys cigars is given below;

Given that, the probabilities are

The customers who purchased cigars be 0.02

The customers who purchased cigars + beer 0.50

And, the customers who purchased beer + cigars be 0.25

Now the probabilities where the customer purchased both

= 0.05 × 0.02

= 0.10

The probability where the customer purchased beer is

= 0.01 ÷ 0.25

= 0.04

Now the probability where a customer neither buys beer nor buys cigars is

= 1 - 0.02 + 0.04 - 0.01

= 0.95

4 0

2 years ago