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2 years ago

A charity organization is having a fundraiser.

Mathematics

1 answer:

nignag [31]2 years ago

6 0

Answer:

Hence, the price of single ticket is $70.

Step-by-step explanation:

Consider the provided equation.

$P(n) = 70n - 1500$

As we know that: Profit = Income – Cost

Here, P(n) represents the fundraiser's profit (in dollars) and n represents the number of tickets sold and cost is 1500

Since, n is multiplied by 70 that represents the price of per ticket is $70.

Hence, the price of single ticket is $70.

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Given the general identity tan X =sin X/cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?

irakobra [83]

First, note that $m\angle A+m\angle C=90^{\circ}.$ Then

$m\angle A=90^{\circ}-m\angle C \text{ and } m\angle C=90^{\circ}-m\angle A.$

Consider all options:

$\tan A=\dfrac{\sin A}{\sin C}$

By the definition,

$\tan A=\dfrac{BC}{AB},\\ \\\sin A=\dfrac{BC}{AC},\\ \\\sin C=\dfrac{AB}{AC}.$

Now

$\dfrac{\sin A}{\sin C}=\dfrac{\dfrac{BC}{AC}}{\dfrac{AB}{AC}}=\dfrac{BC}{AB}=\tan A.$

Option A is true.

$\cos A=\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}.$

By the definition,

$\cos A=\dfrac{AB}{AC},\\ \\\tan (90^{\circ}-A)=\dfrac{\sin(90^{\circ}-A)}{\cos(90^{\circ}-A)}=\dfrac{\sin C}{\cos C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AC}}=\dfrac{AB}{BC},\\ \\\sin (90^{\circ}-C)=\sin A=\dfrac{BC}{AC}.$

Then

$\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}=\dfrac{\dfrac{AB}{BC}}{\dfrac{BC}{AC}}=\dfrac{AB\cdot AC}{BC^2}\neq \dfrac{AB}{AC}.$

Option B is false.

$\sin C = \dfrac{\cos A}{\tan C}.$

By the definition,

$\sin C=\dfrac{AB}{AC},\\ \\\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.$

Now

$\dfrac{\cos A}{\tan C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{AB}{BC}}=\dfrac{BC}{AC}\neq \sin C.$

Option C is false.

$\cos A=\tan C.$

By the definition,

$\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.$

As you can see $\cos A\neq \tan C$ and option D is not true.

$\sin C = \dfrac{\cos(90^{\circ}-C)}{\tan A}.$

By the definition,

$\sin C=\dfrac{AB}{AC},\\ \\\cos (90^{\circ}-C)=\cos A=\dfrac{AB}{AC},\\ \\\tan A=\dfrac{BC}{AB}.$

Then

$\dfrac{\cos(90^{\circ}-C)}{\tan A}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AB}}=\dfrac{AB^2}{AC\cdot BC}\neq \sin C.$

This option is false.

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Leokris [45]

To answer this question, you need to makes the unit of the smartphone screen same. In this case, phone A is using decimal and phone B is using a fraction. You can use which was easier.
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Write 9.054 X 10-6 in standard form.

Kryger [21]

Answer:

0.000009054

Have a nice day!!! :-)

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2 years ago

You are typing a paper. At 4:04pm you have typed 275 words. By 4:18pm you have 765 words. Find the rate of change in words per m

alekssr [168]

You start at 4:04pm and end at 4:18pm. This means 14 minutes have passed

Now you had 275 word typed and now you have 765. To find the amount that were added simply subtract 765 by 275 and you'll get 490.

Finally, to find the average amount of words typed per minute, you'd divide 490 by 14 for each minute which is 35

Your answer is 35 words per minute

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1 year ago

Miguel created the ratio table below to show how he uses the money he earns at work. How much money will he save if he earns 120

loris [4]

Answer:

The money he will save if he earns $120.00 is <u> $90.00</u>.

Step-by-step explanation:

Given:

In the figure is the ratio of the savings and the earnings.

Now, to find out that how much savings will be if Miguel earns $120.00.

We need to get the percentage of the ratio of the earning and saving.

So, according to the table: