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vichka [17]
2 years ago
7

An airplane is flying at a speed of 500 mi/h at an altitude of one mile. The plane passes directly above a radar station at time

t = 0.
(a) Express the distance s (in miles) between the plane and the radar station as a function of the horizontal distance d (in miles) that the plane has flown.
s(d) =
(b) Express d as a function of the time t (in hours) that the plane has flown.
d(t) =
(c) Use composition to express s as a function of t.
s(t) =
Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
6 0

Answer:

a)s=\sqrt{1+d^2}

b)d(t)=500t

c)s(t) =\sqrt{1+250000t^2}

Step-by-step explanation:

d = Horizontal distance

s = the distance between the plane and the radar station

The horizontal distance (d), the one mile altitude, and s form a right triangle.

So, use Pythagoras theorem

Hypotenuse^2=Perpendicular^2+Base^2

s^2=1^2+d^2

a) s=\sqrt{1+d^2}

(b) Express d as a function of the time t (in hours) that the plane has flown.

distance = speed \times time

d(t)=500t

(c) Use composition to express s as a function of t.

s(t) =\sqrt{1+d^2}

using b

s(t) =\sqrt{1+(500t)^2}\\s(t) =\sqrt{1+250000t^2}

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Step-by-step explanation:

Given that sum is equal = 210

Lets ( x, y, z ) be the three positive numbers

such that

x + y + z = 210

what is the maximum of xyz

take f(x,y,z) = xyz

Q(x,y,z) = 0

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consider the function

F(x,y,z) = f(x,y,z) + λQ(x,y,z)

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dF/dy = 0 ⇒ xz + λ(1) = 0 ⇒ λ = -xz.................equ(2)

dF/dz = 0 ⇒ xy + λ(1) = 0 ⇒ λ = -xy...............equ(3)

Now

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MAXIMUM

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