the final price of the wind chime is $29.925 .
<u>Step-by-step explanation:</u>
Here we have , A home improvement store sold wind chimes for $30 each. A customer signed up for a free membership card and received a 5% discount off the price. Sales tax of 5% was applied after the discount. We need to find What was the final price of the wind chime . Let's find out:
Initially we have , 5% discount in $30 i.e.
⇒ (30(5))/100
⇒ (150)/100
⇒ $1.5 , So now price becomes $30 - $1.5 = $28.5 . At this amount there's 5% tax i.e.
⇒ (28.5(5))/100
⇒ (142.5)/100
⇒ $1.425
So now price becomes $28.5 + $1.425 = $29.925 . Therefore , the final price of the wind chime is $29.925 .
Answer:
x = -2
Step-by-step explanation:
From x = -2 to x = 5, f' is negative. That means f is decreasing.
From x = 5 to x = 6, f' is positive. That means f is increasing.
The negative area (between x = -2 and x = 5) is larger than the positive area area (between x = 5 and x = 6). That means f decreases more than it increases.
So f is an absolute maximum at x = -2.
Answer:
a) 1/10 x 5/10 = 1/20
b) 1/10 x 5/9 = 1/18
Step-by-step explanation:
<h2>
Answer:</h2>
<h2>
Step-by-step explanation:</h2>
I've drawn a graph in order to a better understanding of this problem. We know that:
BC is perpendicular to AC
∠DBE = 2x - 1
∠CBE = 5x - 42
Let's call the intersection of line BC and AC the point P, so:
∠P=90°
And points B, P and C form the triangle ΔBPC. On the other hand, ∠CBE and ∠PCB are Alternate Interior Angles, so:
∠PCB = ∠CBE = 5x - 42
Moreover:
∠PBC = 2x - 1 - (5x - 42)
∠PBC = 2x - 1 - 5x + 42
∠PBC = -3x + 41
The internal angles of any triangle add up to 180°. Hence for ΔBPC:
90° + ∠PBC + ∠PCB = 180°
90° - 3x + 41 + 5x - 42 = 180°
2x + 89 = 180
2x = 91
x = 45.5°
Answer:
The length side of the pre-image is 16 units
Step-by-step explanation:
we know that
The length side of the image is equal to the length side of the pre-image multiplied by the scale factor
or
The length side of the pre-image is equal to the length side of the image divided by the scale factor
in this problem we have that
The scale factor is 1/2
The length side of the image is 8 units
therefore
8/(1/2)=16 units
The length side of the pre-image is 16 units