1000:300:750 as a simplified ratio.

Twelve of the 20 students in Mr. Skinner’s class brought lunch from home. Fourteen of the 21 students in Ms. Cho’s class brought

babymother [125]

Solution:

Number of students in Mr.Skinner's class who brought lunch from home if there are 20 students in the class=12

Fraction of students who brought lunch from home in Mr. Skinner's class= $\frac{12}{20}=\frac{3}{5}$

Number of students in Ms. Cho's class who brought lunch from home if there are 21 students in the class=14

Fraction of students who brought lunch from home in Ms. Cho's class= $\frac{14}{21}=\frac{2}{3}$

As Siloni is using two 15-section spinners to simulate randomly selecting students from each class and predicting whether they brought lunch from home or will buy lunch in the cafeteria.

Number of Congruent sectors in each Spinner=15

So, if we represent students from Mr. Skinner's class who brought lunch from home in Spinner having 15 congruent Sectors = $\frac{9}{15}$

So, if we represent students from Mrs. Cho's class who brought lunch from home in Spinner having 15 congruent Sectors = $\frac{10}{15}$

Mr Skinner class +1 = Mr's Cho's Class

So Ms Cho's class =One more sector of the Skinner-class spinner will represent bringing lunch from home.

Option A which is One more sector of the Skinner-class spinner will represent bringing lunch from home represents Ms Cho's Class.

9 0

2 years ago

Read 2 more answers

3. There are about 1.61 kilometers in 1 miles. Let x represent a distance measured in kilometers and y represent the same distan

WINSTONCH [101]

We have been given that there are about 1.61 kilometers in 1 miles.

Let x represent a distance measured in kilometers and y represent the same distance measured in miles.

We can set two equations from the given information as:

$x=\frac{1}{1.16}*y$ (Number of kilometers in terms of number of miles)

$y=1.61*x$ (Number of miles in terms of number of kilometers)

Therefore, $x=\frac{1}{1.16} y$ and $y=1.61*x$ will be our equations.

5 0

2 years ago

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According to Money magazine, Maryland had the highest median annual household income of any state in 2018 at $75,847.† Assume th

Shtirlitz [24]

Answer:

a. 0.3372 or 33.72%; b. 0.2236 or 22.36%; c. 0.2879 or 28.79%; d. $112,351.00

Step-by-step explanation:

We need to use here the values from the <em>cumulative standard normal table</em> and <em>z-scores</em> to solve the questions. That is, all the values are transformed to a <em>z-score</em> to use the <em>standard normal table</em> to find the probabilities. Notice that the question is telling us about the <em>median</em> and not <em>mean</em>. Fortunately, in the normal distribution the mean, the median, and the mode are the same. So, we can say that:

$\\ median\;,mode\;,and\;mean=\mu$

As a result, the parameters for the normal distribution in this case are:

$\\ \mu = 75847\;and\;\sigma=33800$

Then we can solve the questions as follows:

<h3>Part a: Probability that annual income of 90,000 or more</h3>

We need to calculate the z-score of such a value of x=90,000:

$\\ z = \frac{x - \mu}{\sigma}$

$\\ z = \frac{90000 - 75847}{33800}$

$\\ z = \frac{14153}{33800}$

$\\ z = 0.41872$

We need to round this value to z = 0.42 to use the <em>cumulative standard normal table. </em>This value is above the mean (positive) and corresponds, approximately, with a cumulative probability of P(x<90000) = 0.66276.

Then, the probability that a household in Maryland has an annual income of $90,000 or more is:

$\\ P(x\geq90000) = 1 - P(x$

Rounding to four decimal places is 0.3372 or 33.72%

<em>We can follow the same procedure to find the rest of the probabilities asked.</em>

<h3>Part b: Probability a household has an annual income of 50,000 or less.</h3>

$\\ P(x\leq50000) = \?$

$\\ z = \frac{x - \mu}{\sigma}$

$\\ z = \frac{50000 - 75847}{33800}$

$\\ z = -0.764704$

Rounding this value to two decimals (z = -0.76), we can conclude that this value is below the mean. To find this probability from the cumulative standard normal table, we first found the value of z = 0.76 (since no negative value is displayed in this table) and then subtracting this value from one. This is possible because the normal distribution is symmetrical. Then,

$\\ P(z$

Thus, the probability that a household in Maryland has an annual income of $50,000 or less is 0.2236 (rounding to four decimals) or 22.36%.

<h3>Part c: Annual income between $40,000 and $70,000</h3>

Mathematically, it can be expressed as:

$\\ P(40000$

For x = 40000:

$\\ z = \frac{40000 - 75847}{33800}$

$\\ z = -1.06085$

<em>This value is below the mean and is -1.06085 standard deviations from it.</em>

Following the same procedure in Part b, the value for z = -1.06 corresponds to a cumulative probability of (P(z<1.06) = 0.85543):

$\\ P(z$

For x = 70000:

$\\ z = \frac{70000 - 75847}{33800}$

$\\ z = -0.17298$

Which corresponds to a cumulative probability of (P(z<0.17) = 0.56749):

$\\ P(z$

Then, the probability that a household in Maryland has an annual income between $40,000 and $70,000 is:

0.43251 - 0.14457 = 0.28794.

Rounding to four decimals is 0.2879 or 28.79%.

Part d: Eighty-sixth percentile

The z-score that corresponds to a probability of 86% or 0.86 is z = 1.08.

Then, solving the equation for the corresponding z-score:

$\\ 1.08 = \frac{x - 75847}{33800}$

$\\ 1.08*33800= x - 75847$

$\\ 1.08*33800 + 75847 = x$

$\\ x = 112351$

Then, the annual income of a household in the eighty-six percentile of annual household in Maryland is $112,351.00.

8 0

2 years ago

At a sporting event, cheerleaders will throw 50 bundled T-shirts into the crowd. The T-shirt sizes consist of 10 small, 15 mediu

yan [13]

Answer:

The probability that she will catch a T-shirt that is not a size small is $(\frac{4}{5}) .$

Step-by-step explanation:

Here, the total number of shirts thrown in the crowd = 50

The number of small shirts thrown = 10

The number of medium shirts thrown = 15

The number of large/ extra large shirts = Total shirts - ( 10 + 15)

= 50 - 25 = 25

So, in total 25 shirts are thrown in the crowd of large/extra large.

Now, the number shirts which is NOT SMALL size

= Total shirts - Shirts with small size = 50 - 10 = 40

$\textrm{Probability of getting a NOT SMALL t shirt } = \frac{\textrm{The total NOT SMALL t-shirts}}{\textrm{The total number of t shirts}}\\\implies P( \textrm{not small t shirt}) = \frac{40}{50} = \frac{4}{5}$

Hence, the probability that she will catch a T-shirt that is not a size small is $(\frac{4}{5}) .$

4 0

2 years ago

May has 4 /15 meters of lace while Lovie has 2 /7 meter longer than May's lace. how many meters of lace do girls have together

leonid [27]

Answer:

86/105

Step-by-step explanation:

May has 4/15 meters of lace

Lovie has a lace that is 2/7 meters longer

4/5 + 2/7

= 58/105

Therefore the lace they own together can be calculated as follows

= 4/15 + 58/105

= 86/105

Hence together they have 86/105 meters of lace

8 0

2 years ago