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barxatty [35]
1 year ago
7

Tracie rides the bus home from school each day. The graph represents her distance from home relative to the number of minutes si

nce the bus left the school.
A coordinate plane showing Driving Home. The x-axis shows Time in minutes and the y-axis shows Distance from Home in miles. The line starts at (0, 9) and passes through (2, 8), (4, 7), and ends at (10, 4).
What does the slope of the graph mean?

Tracie’s bus travels towards her home at an average speed of StartFraction one-half EndFraction mile per minute.
Tracie’s bus travels towards her home at an average speed of 2 miles per minute.
Tracie’s bus travels away from her home at an average speed of StartFraction one-half EndFraction mile per minute.
Tracie’s bus travels away from her home at an average speed of 2 miles per minute.
Mathematics
2 answers:
kvv77 [185]1 year ago
6 0

Answer:

Tracie’s bus travels towards her home at an average speed of StartFraction one-half EndFraction mile per minute.

Step-by-step explanation:

Semmy [17]1 year ago
4 0

Step-by-step explanation:

Tracie’s bus travels towards her home at an average speed of StartFraction one-half EndFraction mile per minute.

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2. A store is to pack pencils in boxes of 10 and 12 pieces. What is the smallest number of pencils that can be packed using the
Taya2010 [7]

Answer:

2

Step-by-step explanation:

Obtain the greatest common factor of both 12 and 10

Factors of 10 = 1, 2, 5, 10

Factors of 12 = 1, 2, 3, 4, 6, 12

From the above, the greatest common factor of 10 and 12 is 2

Hence, smallest number of pencils using the boxes is 2

3 0
2 years ago
The function below represents the interest Kristina earns on an investment. Identify the term that represents the amount of mone
Elena-2011 [213]

Answer:

The amount of money originally invested which is the principal P = 5,000

Step-by-step explanation:

Using the compound interest formula, the return on investment can be represented on the interest function as;

f(x) = P(1+r)^x

Where

P is the principal which is the initial investment.

r = rate Proportion

x = time (number of years)

Comparing to the given function;

f(x) = 5,000(1 + 0.04)^x

We can see that;

Principal P = 5,000

Rate r = 0.04

time = x

The amount of money originally invested which is the principal P = 5,000

4 0
2 years ago
HELP! A daycare purchases two type of snacks, granola bars and fruit rolls. One week, they purchase 10 packs of granola bars and
ch4aika [34]
10x+6y=152
5x+3y=76
7x+12y=200
-20x-12y=-304
-13x=-104
x=8
40+3y=76
3y=36
y=12
There are 8 granola bars in a pack and 12 fruit rolls in a pack
5 0
2 years ago
Read 2 more answers
Janelle practices basketball every afternoon in the driveway each day her goal is to make four more baskets then she made the da
Alla [95]
She made 62 baskets by day 14. 4×13=52+10=62
5 0
2 years ago
Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles
Ugo [173]

By definition, the average rate of change is given by:

AVR = \frac{f(x2)-f(x1)}{x2-x1}

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2

Evaluating for x = 3:

f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18

Then, the AVR is:

AVR = \frac{18-(-2)}{3-(-2)}

AVR = \frac{18+2}{3+2}

AVR = \frac{20}{5}

AVR = 4


For f (x) = 3x - 8:

Evaluating for x =4:

f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4

Evaluating for x = 5:

f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7

Then, the AVR is:

AVR = \frac{7-4}{5-4}

AVR = \frac{3}{1}

AVR = 3


For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15

Evaluating for x = 4:

f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8

Then, the AVR is:

AVR = \frac{8-15}{4-(-3)}

AVR = \frac{-7}{4+3}

AVR = \frac{-7}{7}

AVR = -1


For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4

Evaluating for x = 1:

f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4

Then, the AVR is:

AVR = \frac{-4-(-4)}{1-(-1)}

AVR = \frac{-4+4}{1+1}

AVR = \frac{0}{2}

AVR = 0


Answer:

from the greatest to the least value based on the average rate of change in the specified interval:


f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]


4 0
2 years ago
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