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barxatty [35]
1 year ago
7

Tracie rides the bus home from school each day. The graph represents her distance from home relative to the number of minutes si

nce the bus left the school.
A coordinate plane showing Driving Home. The x-axis shows Time in minutes and the y-axis shows Distance from Home in miles. The line starts at (0, 9) and passes through (2, 8), (4, 7), and ends at (10, 4).
What does the slope of the graph mean?

Tracie’s bus travels towards her home at an average speed of StartFraction one-half EndFraction mile per minute.
Tracie’s bus travels towards her home at an average speed of 2 miles per minute.
Tracie’s bus travels away from her home at an average speed of StartFraction one-half EndFraction mile per minute.
Tracie’s bus travels away from her home at an average speed of 2 miles per minute.
Mathematics
2 answers:
kvv77 [185]1 year ago
6 0

Answer:

Tracie’s bus travels towards her home at an average speed of StartFraction one-half EndFraction mile per minute.

Step-by-step explanation:

Semmy [17]1 year ago
4 0

Step-by-step explanation:

Tracie’s bus travels towards her home at an average speed of StartFraction one-half EndFraction mile per minute.

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A cube with side length 4p is stacked on another cube with side length 2q^2. What is the total volume of the cubes in factored f
AnnZ [28]
Volume of cube=side³
ok, so you need to know the difference or sum of cubes
a³+b³=(a+b)(x²-xy+y²)
so

(4p)³+(2q²)³=
(4p+2q²)((4p)²-(4p)(2q²)+(2q²)²)=
(4p+2q²)(16p²-8pq²+4q⁴)

3rd option
5 0
1 year ago
You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl
gtnhenbr [62]

Answer:

maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

Step-by-step explanation:

We know that area of circle is given by

A=\pi \times (radius)^{2}

For circle with radius 'r' we have

A_{1}=\pi \times (r)^{2}

For circle with radius 'R' we have

A_{2}=\pi \times (R)^{2}

Now according to given condition we have

A_{1}-A_{2}\leq \frac{5}{\pi }

\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

Thus maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

6 0
2 years ago
There are some nickels dimes and quarters in a large piggy bank for every two nickels there are 3 dimes for every two dimes that
creativ13 [48]

We are given

piggy bank has nickels , dimes and quarters

Let's assume

number of nickels =n

every two nickels there are 3 dimes

so, number of dimes are

=\frac{3}{2}n

=1.5n

every two dimes that are 5 quarters there

so, number of quarters are

=\frac{5}{2}\times 1.5n

=3.75n

so, total number of coins = number of nickels + number of dimes +number of quarters

total number of coins =n+1.5n+3.75

there are 500 coins

so, we get

n+1.5n+3.75n=500

now, we can solve for n

6.25n=500

divide both sides by 6.25

so, we get

n=80

number of dimes is 1.5n

=1.5\times 80

=120

number of quarters  is 3.75n

=3.75\times 80

=300

so,

Number of nickels =80

Number of dimes =120

Number of quarters =300............Answer

6 0
2 years ago
Divide 42 in a ratio of 1:2:3
Vilka [71]

the ratio in which 42 should be divided is 1:2:3

the sum of the parts of the ratio is - 1 + 2 + 3 = 6

this means that there's a sum of 6 parts

so we need to find how much 1 part is equivalent to

if 6 parts are equivalent to 42

then 1 part is equivalent to - 42/6 = 7

so the ratio should be 1:2:3

1 part - 7

2 parts - 7 x 2 = 14

3 parts - 7 x 3 = 21

therefore 42 divided into 1:2:3 ratio is as follows

7 : 14 : 12

4 0
1 year ago
Read 2 more answers
Sophia was selling tickets at the high school dance. At the end of the evening, she picked up the cash box and noticed a $5 bill
borishaifa [10]
The first thing we will do in this case is to define variables:
 x = number of individual tickets.
 y = number of tickets per couple.
 We have then that the system of equations that represents the problem is:
 10x + 15y = 590
 x + 2y = 68
 Solving the system we have:
 x = 32
 y = 18
 Substituting we have:
 10 (32) + 15 (18) = 590
 320 + 270 = 590
 590 = 590
 Equality is met, therefore the $ 5 bill belongs to the box.
 Answer:
 
the $ 5 bill belong inside the cash box
4 0
2 years ago
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