Volume of cube=side³
ok, so you need to know the difference or sum of cubes
a³+b³=(a+b)(x²-xy+y²)
so
(4p)³+(2q²)³=
(4p+2q²)((4p)²-(4p)(2q²)+(2q²)²)=
(4p+2q²)(16p²-8pq²+4q⁴)
3rd option
Answer:
maximum difference of radii =
Step-by-step explanation:
We know that area of circle is given by

For circle with radius 'r' we have

For circle with radius 'R' we have

Now according to given condition we have


Thus maximum difference of radii =
We are given
piggy bank has nickels , dimes and quarters
Let's assume
number of nickels =n
every two nickels there are 3 dimes
so, number of dimes are


every two dimes that are 5 quarters there
so, number of quarters are


so, total number of coins = number of nickels + number of dimes +number of quarters
total number of coins =n+1.5n+3.75
there are 500 coins
so, we get

now, we can solve for n

divide both sides by 6.25
so, we get

number of dimes is 1.5n


number of quarters is 3.75n


so,
Number of nickels =80
Number of dimes =120
Number of quarters =300............Answer
the ratio in which 42 should be divided is 1:2:3
the sum of the parts of the ratio is - 1 + 2 + 3 = 6
this means that there's a sum of 6 parts
so we need to find how much 1 part is equivalent to
if 6 parts are equivalent to 42
then 1 part is equivalent to - 42/6 = 7
so the ratio should be 1:2:3
1 part - 7
2 parts - 7 x 2 = 14
3 parts - 7 x 3 = 21
therefore 42 divided into 1:2:3 ratio is as follows
7 : 14 : 12
The first thing we will do in this case is to define variables:
x = number of individual tickets.
y = number of tickets per couple.
We have then that the system of equations that represents the problem is:
10x + 15y = 590
x + 2y = 68
Solving the system we have:
x = 32
y = 18
Substituting we have:
10 (32) + 15 (18) = 590
320 + 270 = 590
590 = 590
Equality is met, therefore the $ 5 bill belongs to the box.
Answer:
the $ 5 bill belong inside the cash box