Answer:
- <u><em>Option b. just below 30%</em></u>
<u><em></em></u>
Explanation:
Please, see attached the <em>histogram that represents the distribution of acceptance rates (percent accepted) among 25 business schools in 2004. </em>
<em />
The<em> median</em> is the value that separates the lower 50% from the upper 50% of the data.
Since there are 25 business schools, the middle value is the number 13.
The height of each bar is the<em> frequency</em> or number of business school for that acceptace rate:
- The first bar has frequency of 1 school
- The second bar has frequency of 3 schools: cummulative frequency: 1+3=4.
- The third bar has frequency 5 schools: cummulative frequency 4 + 5 = 9.
- The fourth bar has frequency 3 schools: cummulative frequency: 9+3=12.
Then, the 13th value is on the next bar, the fifth bar.
The fifth bar has acceptance rates 25 ≤ rate < 30.
That means that the median acceptance rate is greater than or equal to 25 and less than 30.
Thus, the choice is the option <em>b. just below 30%.</em>
<span>All the information we have are the probabilities, and what we need is the lowest number: so let's choose the smallest probability among the numbers: 0.0065%, B 0.0037%,C 0.0108%,D 0.0029%, E 0.0145%. The smallest of the numbers is 0.0029% -it starts with two 00s and the number that follows, 2, is smaller than all there others - so the smallest probability is in option D - and the model would be the corresponding model (but we're missing some information here) </span>
Answer:
a). AB = 8 in
b). AB = 9.75 in
c). AC = 6.5 in
d). BC = 1.5 in
Step-by-step explanation:
a). Since, AB = AC + CB
Length of AC = 5 in. and CB = 3 in.
Therefore, AB = 5 + 3 = 8 in.
b). Given : AC = 6.25 in and CB = 3.5 in
Therefore, AB = AC + CB = 6.25 + 3.5
AB = 9.75 in.
c). Given: AB = 10.2 in. and BC = 3.7 in.
AB = AC + BC
AC = AB - BC
AC = 10.2 - 3.7
AC = 6.5 in
d). Given: AB = 4.75 in and AC = 3.25 in.
BC = AB - AC
BC = 4.75 - 3.25 = 1.5 in.
Answer:
B.
Step-by-step explanation:
Because if you subtract 19x and 18 from each side it wont be 0=0, in other equatins there is infinity solutions
