After a reflection across line L1, x = 2, the afterimage is
Z' (2 + (2-1) ,1) = Z' (3, 1)
After a reflection across the line L2, y-axis, the afterimage is
Z'' (3, 0 + (0 - 1) = Z'' (3, -1)<span />
Answer:
B) 30
Step-by-step explanation:
Bill saves 60 dollars a month so first you have to find out how much he saves in a year
To find that you multiply 60 by 12 since there are 12 months in a year
60*12 = 720
Tom saves 750 in a year so you have to subtract 750 by 720 to know how much more tom saves
750 - 720 = 30
Answer:
<h2> 105 tickets</h2>
Step-by-step explanation:
To solve this problem we need to model an equation to represent the situation first.
the goal is to archive $7500 in the even, bearing in mind that there is a cost of $375 fee for rent, we need to put this amount into consideration
let the number of tickets be x
so
75x-375>=7500--------1
Equation 1 above is a good model for the equation
we can now solve for x to determine the number of tickets to be sold to archive the aim
75x-375>=7500--------1
75x>=7500+375
75x>=7875
divide both sides by 75 we have
x>=7875/75
x>=105 tickets
so they must sell a total of 105 tickets and above to meet the target of $7500 with the rent inclusive
First, add the profit wanted with the costs.
1500 + 200 + 100 = 1800
The total amount wanted is 1800. Each student pays $5, and so you divide by 5
1800/5 = 360
360 students must show up.
The equation used is:
Let student = s
Total cost = 200 + 100
Charge = 5n
Profit = 1500
1500 = 5n - 300 (is equation)
Hope this helps
76,500/100,000 divide by 100
765/1,000. divide by 5
153/500
