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Dafna1 [17]
2 years ago
12

A small company’s net income for the first six months of the year was $76,500 and for the last six months it was $100,000. What

is the ratio of the first six months of the year to the last six months of the year in simplest form?
Mathematics
2 answers:
algol [13]2 years ago
5 0

Answer:

Ratio of the first 6 months and last six months is 153 : 200

Step-by-step explanation:

Net income for the last six months of the year = $76500

Net income of the last six months = $100000

Now we have to find the ratio of income in the first six months to the income in the last six months.

= \frac{\text{Income in the first six months}}{\text{Income in the last six months}}

= \frac{76500}{100000}

= \frac{765}{1000}

=  \frac{153}{200}

Therefore, the ratio of the incomes in two halves of a year is 153 : 200

worty [1.4K]2 years ago
4 0
76,500/100,000 divide by 100
765/1,000. divide by 5
153/500
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Lemur [1.5K]

Answer:

Hypothesis rejected

Step-by-step explanation:

Lets use the t-test since the variance of the population is now known. We need to test the hypothesis that H_0: \mu \leq 79 \text{ vs } H_1: \mu > 79 . This is performed in R as follows:

t.test(tt$Test.2.Score,mu=79,alternative="greater")

One Sample t-test

data: tt$Test.2.Score

t = 2.9238, df = 69, p-value = 0.002337

alternative hypothesis: true mean is greater than 79

95 percent confidence interval:

81.26555 Inf

sample estimates:

mean of x

84.27143

Thus, we reject the null hypothesis and conclude that \mu > 79.

4 0
2 years ago
7.3 x 9.6 = <br>how to show your work
ss7ja [257]
The correct answer is 70.08 all you have to do is multiply them together. 
4 0
2 years ago
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A sequence is defined by mc024-1.jpg, and mc024-2.jpg. What is the seventh term?
abruzzese [7]
Given data :
a₃ = 9/16
aₓ = -3/4 · aₓ₋₁
Where x is the number of terms ('x' is also written as 'n')
To find the 7th term (a₇):

We know that aₓ = -3/4 · aₓ₋₁
So,
a₃ = -3/4 · a₃₋₁
a₃ = -3/4 · a₂
9/16 = -3/4 · a₂
a₂ = 9/16 × -4/3
a₂ = -36/48
a₂ = -3/4

Again,
aₓ = -3/4 · aₓ₋₁
a₄ = -3/4 · a₄₋₁
a₄ = -3/4 · a₃
a₄ = -3/4 · 9/16
a₄ = -27/64
a₄ = -27/64

For a₅,
aₓ = -3/4 · aₓ₋₁
a₅ = -3/4 · a₅₋₁
a₅ = -3/4 · a₄
a₅ = -3/4 × -27/64
a₅ = 81/256

For a₆,
aₓ = -3/4 · aₓ₋₁
a₆ = -3/4 · a₆₋₁
a₆ = -3/4 · a₅
a₆ = -3/4 × 81/256
a₆ = -243/1024

For a₇,
aₓ = -3/4 · aₓ₋₁
a₇ = -3/4 · a₇₋₁
a₇ = -3/4 · a₆
a₇ = -3/4 × -243/1024
a₇ = 729/4096
3 0
2 years ago
Read 2 more answers
A flea treatment last 4 weeks. Jim's dog had to be treated every 3 weeks. How many weeks of flea treatment would Jim's dog get i
Reptile [31]

Answer:

Number of weeks in a year = 52 weeks

If in a normal year when each package of flea treatment lasts for 4 weeks, then in a year there Jim's dog will have to be treated for

Where as, when the fleas are bad in a year, the treatment lasts for only 3 weeks.

Then in a year Jim's dog would get

So Jim's dog will get 17- 13 =4 treatments more.

4 treatments that are made in 3 weeks each will be 4×3 =12 weeks more treatment

6 0
2 years ago
Which of these objects has the largest diameter? • Sun • Cricket Bat • Tennis Ball • Moon
Fed [463]
The moon does. The moon is waaaay bigger than any of these combined.
8 0
1 year ago
Read 2 more answers
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