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Dafna1 [17]
1 year ago
12

A small company’s net income for the first six months of the year was $76,500 and for the last six months it was $100,000. What

is the ratio of the first six months of the year to the last six months of the year in simplest form?
Mathematics
2 answers:
algol [13]1 year ago
5 0

Answer:

Ratio of the first 6 months and last six months is 153 : 200

Step-by-step explanation:

Net income for the last six months of the year = $76500

Net income of the last six months = $100000

Now we have to find the ratio of income in the first six months to the income in the last six months.

= \frac{\text{Income in the first six months}}{\text{Income in the last six months}}

= \frac{76500}{100000}

= \frac{765}{1000}

=  \frac{153}{200}

Therefore, the ratio of the incomes in two halves of a year is 153 : 200

worty [1.4K]1 year ago
4 0
76,500/100,000 divide by 100
765/1,000. divide by 5
153/500
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Victor fue al mercado para comprar manzanas, naranjas y platanos; las naranjas costaron el doble de lo 1ue pago por las manzanas
Thepotemich [5.8K]

Answer:

El precio de las manzanas = 27 pesos

El precio de las naranjas = 54 pesos

El precio de las bananas = 19 pesos

Step-by-step explanation:

Los parámetros dados son;

El monto total gastado = 100 pesos

Sea el precio de las naranjas = x

Sea el precio de las manzanas = y

Sea el precio de los plátanos = z

La cantidad pagada por las naranjas = 2 · y = x

La cantidad pagada por los plátanos = y - 8 = z

Por lo tanto, tenemos;

La cantidad total gastada = La cantidad pagada por las naranjas + La cantidad pagada por las bananas + La cantidad pagada por las manzanas

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100 = 4 · años - 8

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y = 108/4 = 27

y = 27

De

z = y - 8 tenemos;

z = 27 - 8 = 19

De 2 · y = x, tenemos;

2 × 27 = x

x = 54

Por lo tanto;

El precio de las naranjas = 54 pesos

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1 year ago
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2 years ago
For which discriminant is the graph possible<br> b2-4ac=0<br><br> b2-4ac=-1<br><br> b2-4ac=4
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Answer:

The graph is possible for b^2-4ac=4

Step-by-step explanation:

we know that

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ax^{2} +bx+c=0

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D=b^2-4ac

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If D>0 the quadratic equation has two real solutions

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In this problem , looking at the graph, the quadratic equation has two real solutions (the solutions are the x-intercepts)

so

b^2-4ac > 0

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