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Alex73 [517]
1 year ago
6

Eliza's backpack weighs 18 and StartFraction 7 over 9 EndFraction pounds with her math book in it. Without her math book, her ba

ckpack weighs 14 and StartFraction 7 over 8 EndFraction pounds. How much does Eliza's math book weigh? 3 and StartFraction 11 over 72 EndFraction pounds 3 and StartFraction 65 over 72 EndFraction pounds 4 and StartFraction 11 over 72 EndFraction pounds 4 and StartFraction 65 over 72 EndFraction pounds
Mathematics
1 answer:
kati45 [8]1 year ago
7 0

Answer:

Math\ Book = 3\frac{65}{72}\ kg

Step-by-step explanation:

Given

<em />Backpack = 18\frac{7}{9}kg<em> --- with math book</em>

<em />Backpack = 14\frac{7}{8}kg<em> --- without math book</em>

<em />

Required

Determine the weight of her math book

To do this, we simply calculate the difference in the weights given.

Math Book= Backpack(with math book) - Backpack (without math book)

Math\ Book = 18\frac{7}{9} - 14\frac{7}{8}

Math\ Book = \frac{169}{9} - \frac{119}{8}

Take LCM

Math\ Book = \frac{8 * 169 - 9 * 119}{72}

Math\ Book = \frac{1352 - 1071}{72}

Math\ Book = \frac{281}{72}

Math\ Book = 3\frac{65}{72}\ kg

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Which graph shows the solution set of the compound inequality 1.5 x minus 1 greater-than 6.5 or 7 x + 3 less-than negative 25?
saul85 [17]

Answer:

After solving the compound inequality 1.5x-1>6.5 \ or \ 7x+3 we get \mathbf{x>5 \ or \ x

Option B is correct.

Step-by-step explanation:

We are given compound inequality: 1.5x-1>6.5 \ or \ 7x+3

We will first solve the inequalities to find the value of x, then will draw the graph.

1.5x-1>6.5 \ or \ 7x+36.5+1 \ or \ 7x+3-37.5 \ or \ 7x\frac{7.5}{1.5} \ or \ x5 \ or \ x< -4

So, after solving the compound inequality 1.5x-1>6.5 \ or \ 7x+3 we get \mathbf{x>5 \ or \ x

Now, the number line will be as shown in figure.

The description as given in options is:

A number line goes from negative 10 to positive 10. An open circle appears at negative 4 and positive 5. The number line is shaded from negative 4 toward negative 10. The number line is also shaded from positive 5 toward positive 10.

so, Option B is correct.

5 0
1 year ago
Read 2 more answers
A botanist predicts that the height of a certain tree will increase by 2% every year. If the height of the tree is now 50 feet,
Neporo4naja [7]
To answer this kinda question, we gotta tackle it year by year. 
By the end of the first year, the tree would grow by 2% = 102% of its original height.
Year 1: 102% x 50 = 51 feet
Year 2: 103% x 51 = 52.02 feet

Hope I helped!! xx
4 0
2 years ago
A fisherman is interested in whether the distribution of fish caught in Green Valley Lake is the same as the distribution of fis
maks197457 [2]

Answer:

p = 0.293

Conclusion:

"There is insufficient evidence to state that the distribution of fish in Green Valley Lake is not the same as the distribution of fish in Echo Lake."

Step-by-step explanation:

------------R/trout--O/trout---bass--catfish---total

GVL - - - 105 - - - 27 - - - - - 35--- 24 - - - 191

EL - - - - 135------- 48-------- 67 - - 43 - - - 293

Total - - 240 - - - 75 - - - - - 102--- 67 - - - 484

Note : GVL = GREEN VALLEY LAKE ; EL = ECHO LAKE.

H0: The distribution of fish caught in green valley is the same as that caught in Echo lake.

H1: The distribution of fish caught in Green Valley lake is different from that caught in Echo valley lake.

Using the chi-squared test statistic calculator ;

χ2 = 3.7269

p-value = 0.2925.

p-value = 0.293

Conclusion:

"There is insufficient evidence to state that the distribution of fish in Green Valley Lake is not the same as the distribution of fish in Echo Lake."

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1 year ago
A point x is 34m due to east of a point Y . The bearing of a flagpole from x and Y are N18°W And N40°E respectively .
Murljashka [212]

Answer:

The distance of flag post from Y is 38.13 m

Step-by-step explanation:

Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.  

Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.  

Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.  

Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,  

\angle AXY=\angle AXF+\angle FXY

\therefore 90 \degree=18\degree+\angle FXY

\angle FXY=72\degree

Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,  

\angle BYX=\angle BYF+\angle FYX

\therefore 90 \degree=40\degree+\angle FYX

\angle FYX=50\degree

Refer attachment 1.  

From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.

∠YFX+∠FYX+∠FXY=180°

∠YFX+50°+72°=180°

∠YFX=58°

Refer attachment 2.  

Now the distance FY can be calculated using sin rule as follows,  

\frac{\sin X}{FY}=\frac{\sin F}{YX}=\frac{\sin Y}{FX}

Substituting the values,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}=\frac{\sin 50}{FX}

Simplifying first two terms,

\frac{\sin 72}{FY}=\frac{\sin 58}{34}

Cross multiplying,

34\times\sin 72=FY\times \sin 58

\dfrac{34\times\sin 72}{\sin 58}=FY

FY=38.13 m

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I think it’s 220 inches
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