Answer: $2,442
Step-by-step explanation:
P=2000
r= 4%= 4/100= 0.04
t= 5 years
A is therefore 2000e0.04(5)
=2000e0.2
=$2,442.8
To the nearest dollar will give $2,442
The first thing we will do in this case is to define variables:
x = number of individual tickets.
y = number of tickets per couple.
We have then that the system of equations that represents the problem is:
10x + 15y = 590
x + 2y = 68
Solving the system we have:
x = 32
y = 18
Substituting we have:
10 (32) + 15 (18) = 590
320 + 270 = 590
590 = 590
Equality is met, therefore the $ 5 bill belongs to the box.
Answer:
the $ 5 bill belong inside the cash box
Given:

To find:

Solution:
We have,
and
.
Let the values of h and k are 2a and 5a respectively.
Let the values of x and y are 3b and 4b respectively.
We have,

It can be written as




On further simplification, we get




Now,




On further simplification, we get




Therefore, the ratio
is
.
The height of the project becomes zero when it hits the ground which is also the total time at which the projectile stays in the air. Equating the function to zero:
-10(x)(x - 4) = 0
The roots of this quadratic equation are:
x = 0, and x=4
Therefore, the projectile stays in the air for
4 seconds
answer is 132
because the whole amount of the oranges is 150 so the unsold 82 percent will be 132