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WITCHER [35]
1 year ago
10

A water well is being drilled in the desert where soil is either rock, clay, or sand. Probability of rock P(R) = 0.42, probabili

ty of clay P(C) = 0.34, and probability of sand P(S) =0.24. A geological test gives positive results with 40% accuracy in rock, 50% accuracy with clay, and 80% accuracy in sand. Given the test is positive, what is the probability that the soil is rock, P(Rock|positive)? Use Bayes’ rule.
Mathematics
2 answers:
Zanzabum1 year ago
7 0
The probality is 19.5
andrezito [222]1 year ago
6 0

We are asked to solve for:

P (sand | positive)

So, we solve this by:

P (sand | positive) = P (sand)  x P (positive for sand)

P (sand | positive) = 0.26 (0.75)

P (sand | positive) = 0.195

The probability is 0.195 or 19.5%.

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Explain how one whole, one tenth, and one hundredth are related
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The solid graph is a translation of RootIndex 3 StartRoot x EndRoot. On a coordinate plane, 2 cube root functions are shown. The
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Step-by-step explanation:

If you take a look at the graph, it shows that it is 2 units up from where it initially started, therefore it is moved 2 units up. It says the SOLID graph is the translation, therefore it would be moving 2 units up.

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An old rectangular tank with length 0.3 m could hold 154 L of water. A new similar tank has a length of 1.5 m. What is the capac
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La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el
Vika [28.1K]

Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

F = kws² / r

Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

w = 1600 libras

r = 800

s = 50 mph

Tenga en cuenta que desde el

F = kws² / r

400 = k × 1600 × 50² / 800

400 = k × 5000

k = 400/5000

k = 2/25

Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

7 0
2 years ago
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