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2 years ago

What is the solution to –2(5y – 5) – 3y ≤ –7y + 22?

2 answers:

6 0

-2(5y - 5) - 3y < = -7y + 22
-10y + 10 - 3y < = -7y + 22
-13y + 10 < = -7y + 22
-13y + 7y < = 22 - 10
-6y < = 12
y > = -12/6
y > = -2....answer B

slavikrds [6]2 years ago

4 0

Answer:

Option: B is the correct answer.

y≥ -2

Step-by-step explanation:

We are asked to find the solution of the inequality:

–2(5y – 5) – 3y ≤ –7y + 22.

We will solve for the inequality as:

-2×5y-2×(-5)-3y ≤ -7y+22 (on solving for the parantheses in the left hand side of the inequality)

-10y+10-3y ≤ -7y+22

⇒ -10y+7y-3y ≤ 22-10 (on combining the like terms)

⇒ -6y ≤ 12

⇒ y≥ -2 (on dividing both side by -6 also the sign of the inequality changes as the negative sign is treated on both the side)

Hence option: B is the correct answer.

y ≥ -2.

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Bob, Bill, and Joe measured their heights. They figured out that the height of Bob is equal to b cm and he makes up 8/9 of the h

andrezito [222]

Answer:

Joe is 12 times taller than Bob

No the answer not rely on the meaning of b

Step-by-step explanation:

* Lets explain how the solve the problem

- The height of Bob is equal to b cm

- The height of Bob is 8/9 of the height of Bill

- Because 8/9 is less than one , then Bob is shorter than Bill

- The height of Bill makes up 3/32 of the height of Joe

* Lets write these information by mathematics relation

∵ The height of Bob is b

∵ The height of Bob is 8/9 height of Bill

∴ b = 8/9 the height of Bill

- Multiply both sides by 9

∴ 9 b = 8 the height of Bill

- Divide both sides by 8

∴ 9/8 b = the height of Bill

∴ The height of Bill is 9/8 b

∵ The height of Bill is 3/32 the height of Joe

∴ 9/8 b = 3/32 the height of Joe

- Multiply both sides by 32

∴ 36 b = 3 the height of Joe

- Divide both sides by 3

∴ 12 b = the height of Joe

∴ The height of Joe is 12 b

∵ b is the height of Bob

∴ The height of Joe is 12 times the height of Bob

∴ Joe is 12 times taller than Bob

- NO, the answer doesn't depend on b because the ratio between the

heights of Joe and Bob doesn't change by the change of b

8 0

2 years ago

In the parallelogram AXYZ, line segment AT = 4y – 2, line segment TY = 6x -12, line segment TX = 14, line segment ZT = 2x + 12.

Tpy6a [65]

In a parallelogram diagonals bisect each other,
=>AT=TX=>4y-2=14=>4y=14+2=>4y =16=>y=16/4=4
And ZT=TY=>2x+12=6x-12
=>12+12=6x-2x
=>24=4x
=>24/4=X
=>6=X
Hope this helps u...!!!

8 0

2 years ago

A circle has a circumference of \blue{12}12start color #6495ed, 12, end color #6495ed. It has an arc of length \dfrac{8}{5} 5 8

Thepotemich [5.8K]

Answer:

Therefore,

The Central Angle is 48°.

Step-by-step explanation:

Given:

Circumference = 12 units

$Arc\ length = \dfrac{8}{5}= 1.6\ unit$

To Find:

Central angle = θ = ?

Solution:

If "θ" the central angle is in degree then arc of length is given by

$Arc\ length = \dfrac{\theta}{360}\times Circumference$

Substituting the values we get

$1.6 = \dfrac{\theta}{360}\times 12\\\\\theta = 48\°$

Therefore,

The Central Angle is 48°.

6 0

2 years ago

Read 2 more answers

A store has clearance items that have been marked down by 60% they having a sale, advertising an additional 30% off clearance it

bagirrra123 [75]

The original price is 100% of the price. If the price is marked 60% off, then you pay 40% of the original price.

An item costs x dollars.

With the 60% off discount, it now costs 40% of x, or 0.4x.

Now you apply a 30% discount.

For the second discount, consider the price 0.4x to be the new original price. If the price is now discounted 30%, you will pay 70% of the new original price.

Start with 0.4x.

Now calculate 70% of 0.4x.

70% of 0.4x = 0.70 * 0.4x = 0.28x

After applying the 60% discount and the 30% discount, the item that originally cost x now costs 0.28x. 0.28x is the same as 28% of x. The amount you pay is 28% of the original price.

Answer: 28%

3 0

2 years ago

Anton will be constructing a segment bisector with a compass and straightedge, while Maxim will be constructing an angle bisecto

Genrish500 [490]

The similarities are;

Compass and a straight edge required for both construction

Both construction includes a line drawn from the intersection of arcs to bisect a segment or an angle

The bases for the construction of both bisector are the ends of segment and the angle to be bisected

The width of the compass when drawing intersecting arcs, is more than half the width of the segment or angle being bisected

The differences are;

Two points of intersection of arcs are used in the segment bisector while only one is requited in an angle bisector
The bisecting line crosses the segment in a segment bisector, while it stops at the vertex of the angle being bisected in an angle bisector

The sources of the above equations are as follows;

The steps to construct a segment bisector are;

Place the needle of the compass at one of the ends of the line segment to be bisected

Widen the compass so as to extend more than half of the length of the segment to be bisected

Draw two arcs, one above, and the other below the line

Place the compass needle at the other end and with the same compass width draw arcs that intersects with the arcs drawn in the above step

Draw a line segment by placing the ruler on the points of intersection of the arcs above and below the line

The steps to construct an angle bisector are;

With the compass needle at the vertex, open the pencil end such that arcs can be drawn on the rays (lines) forming the angle

Draw an arc on both lines forming the angle

Place the compass needle at one of the intersection points and draw an arc in between the lines forming the angle

Repeat the above step with the same compass width from the other intersection point with the rays forming the angle

Join the point of intersection of the two arcs to the vertex of the angle to bisect the angle

Therefore, we have;

The similarities are;

A compass and a straight edge can be used for both construction

A straight line is drawn from the point of intersection of arcs to bisect the segment or the angle

The arcs are drawn from the ends of the segment or angle to be bisected

The width of the compass is more than half the width of the line or angle when drawing the arcs

The differences are;

In a segment bisector, the intersection point is above and below the line, while in an angle bisector only one pair of arcs are drawn to intersect above the line

The bisecting line passes through the segment being bisected, while the line stops at the vertex in an angle bisector

Learn more about the construction of segment and angle bisectors here;

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1 year ago