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madam [21]
2 years ago
15

A metal alloy is a metal made by blending 2 or more types of metal. A jeweler has supplies of two metal alloys. On alloy is 30%

gold and the other is 10% gold. How much of each alloy should the jeweler combine to create 4kg of an alloy containing 15% gold?
Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
6 0

Answer:

He should combine 1 kg of 30% alloy and 3 kg of 10% alloy.

Step-by-step explanation:

Let x = mass of 30% ally.

Let y = mass of 10% alloy.

He needs 4 kg of alloy, so the first equation, dealing with masses, is

x + y = 4

Now we deal with the amount of gold.

He uses x mass of 30% gold alloy. The amount of gold in that mass is 0.3x.

He uses y mass of 10% gold alloy. The amount of gold in that mass is 0.1y.

The total mass of gold is 0.3x + 0.1y. We are told the told the end alloy is 4 kg of 15% gold alloy. That contains 0.15(4) kg = 0.6 kg of gold.

The second equation is

0.3x + 0.1y = 0.6

Now we put together the two equations as a system of equations.

x + y = 4

0.3x + 0.1y = 0.6

Multiply both sides of the second equation by -10.

-3x - y = -6

Add this equation to the first original equation.

         x + y = 4

+     -3x - y = -6

---------------------

        -2x    = -2

            x    = 1

Now substitute x = 1 in the first original equation and solve for y.

x + y = 4

x + y = 4

y = 3

Answer: He should combine 1 kg of 30% alloy and 3 kg of 10% alloy.

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Jacob runs 5 miles in 1 1/2 hours Robert runs 3 miles in 45 minutes who runs faster
Anastasy [175]

Answer:

hence Robert runs at a faster speed

Step-by-step explanation:

1 1/2 hours = 3/2 hours = 1.5 hours

45 min = 45/60 = 3/4 = 0.75 hours

Jacob's speed = 5 miles ÷ 1.5 hours = 3.33 miles/hr

Robert's speed = 3 miles ÷ 0.75 hours = 4 miles/hr

hence Robert runs at a faster speed

6 0
2 years ago
A rectangle is placed around a semi circle as shown below. The width of the rectangle is 7yd. find the area of the shaded region
Nady [450]

Answer:

21.07 yd^2

Step-by-step explanation:

The width of the rectangle is also the radius of the semicircle. The length of the rectangle is 2 radii, or 14 yd.

The area of the shaded region is the same as the area of the semicircle subtracted from the area of the rectangle.

area of shaded region = area of rectangle - area of semicircle

A = LW - (1/2)(pi)r^2

A = 14 yd * 7 yd - (1/2)(3.14)(7 yd)^2

A = 98 yd^2 - (1.57)(49 yd^2)

A = 98 yd^2 - 76.93 yd^2

A = 21.07 yd^2

4 0
1 year ago
You are signing up for a new gym on New Year's Day. Two gyms memberships have different payment plans. Gym A has a $60 signup fe
Romashka-Z-Leto [24]

Answer: August or the 8th month

Step-by-step explanation:

Assuming the month that the costs will be the same is x.

Gym A cost function will be = 60 + 10x

Gym B cost function will be =  20 + 15x

The formula will therefore be;

60 + 10x = 20 + 15x

60 - 20 = 15x - 10x

40 = 5x

x = 8

8th month is August.

6 0
1 year ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
1 year ago
You are converting 8 centimeters to meters. How will the number of meters compare to 8? Explain.
pentagon [3]

The "meter" is a larger unit than the "centimeter." Every time you need to convert a larger metric unit to a smaller one, you must multiply to find a greater value.

6 0
2 years ago
Read 2 more answers
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