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madam [21]
2 years ago
15

A metal alloy is a metal made by blending 2 or more types of metal. A jeweler has supplies of two metal alloys. On alloy is 30%

gold and the other is 10% gold. How much of each alloy should the jeweler combine to create 4kg of an alloy containing 15% gold?
Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
6 0

Answer:

He should combine 1 kg of 30% alloy and 3 kg of 10% alloy.

Step-by-step explanation:

Let x = mass of 30% ally.

Let y = mass of 10% alloy.

He needs 4 kg of alloy, so the first equation, dealing with masses, is

x + y = 4

Now we deal with the amount of gold.

He uses x mass of 30% gold alloy. The amount of gold in that mass is 0.3x.

He uses y mass of 10% gold alloy. The amount of gold in that mass is 0.1y.

The total mass of gold is 0.3x + 0.1y. We are told the told the end alloy is 4 kg of 15% gold alloy. That contains 0.15(4) kg = 0.6 kg of gold.

The second equation is

0.3x + 0.1y = 0.6

Now we put together the two equations as a system of equations.

x + y = 4

0.3x + 0.1y = 0.6

Multiply both sides of the second equation by -10.

-3x - y = -6

Add this equation to the first original equation.

         x + y = 4

+     -3x - y = -6

---------------------

        -2x    = -2

            x    = 1

Now substitute x = 1 in the first original equation and solve for y.

x + y = 4

x + y = 4

y = 3

Answer: He should combine 1 kg of 30% alloy and 3 kg of 10% alloy.

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Answer:

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<u>Step-by-step explanation:</u>

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