h=5 in
w-6 in
l=12 in
SA/V=2*12*6+2*6*5+2*12*5/12*6*5
817:180
This is just an example do not use this exact equation and number! Hope it helps. : )
Answer:
1.95secs
Step-by-step explanation:
Given the height of the float expressed as h(t) = -16t2 - 3t + 55.
The floats reach the swimmer at h(t) = 0
Substitute
0 = -16t^2 - 3t + 55.
16t^2 + 3t - 55 = 0
Using the general formula;
t = -3±√3²-4(16)(-55)/2(16)
t = 3±√9+3520/32
t = 3±√3529/32
t = 3+59.41/32
t = 62.41/32
t = 1.95
Hence it will take 1.95secs
G(h) h
12 3
8 5
4 7
0 9
Equation of the line:
slope = [12-0]/[3-9] = 12 / -6 = -2
g / [h - 9] = -2
g = -2(h-9)
g = -2h + 18
g = 18 -2h
Filling the tank ==> h = 0
g = 18 - 2(0) = 18
Answer: first option g = 18 -2 h; 18
