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frosja888 [35]
2 years ago
9

If container a holds 8 gallons of water and container b holds 12% more than container a, how many gallons of water does containe

r b hold?
Mathematics
1 answer:
frosja888 [35]2 years ago
3 0
Answer: 8.96 gallons of water

To answer this question you need to multiply the container b: container a ratio with the container a volume.
Since container b has more volume than container a, the ratio should be >1. In this case, the ratio is 100%+12%= 112%
Then the volume of container b is= 112% x 8 gallons= 8.96 gallons
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A new technology for the production of integrated circuits is being mastered. The technology will be rejected if the percentage
max2010maxim [7]

Answer:

5901

Step-by-step explanation:

The margin of error is the critical value times the standard error.

ME = CV × SE

For α = 0.05, the critical value is z = 1.96.

The standard error of a proportion is √(pq/n).  Given p = 0.04, then q = 1−p = 0.96.

The margin of error is 0.5% or 0.005.

Plugging in:

0.005 = 1.96 √(0.04 × 0.96 / n)

n ≈ 5901

8 0
1 year ago
A statue is mounted on top of a 16 foot hill. From the base of the hill to where you are standing is 77 feet and the statue subt
DanielleElmas [232]

Consider right triangle with vertices B - base of the hill, S - top of the statue and Y - you. In this triangle angle B is right and angle Y is 13.2°. If h is a height of the statue, then the legs YB and BS have lengths 77 ft and 16+h ft.

You have lengths of two legs and measure of one acute angle, then you can use tangent to find h:

\tan 13.2^{\circ}=\dfrac{\text{opposite leg}}{\text{adjacent leg}} =\dfrac{16+h}{77}, \\ \\ 0.2345=\dfrac{16+h}{77},\\  \\ 16+h=0.2345\cdot 77=18.0565,\\ h=18.0565-16=2.0565 ft.

Answer: the height of the statue is 2.0565 ft.

8 0
1 year ago
Read 2 more answers
Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

(1) When x+2, we have |x+2|=-(x+2) and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4

(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)+(x+2)=4

(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

|x-2|+|x+2|=(x-2)+(x+2)=2x

So

|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x
4 0
1 year ago
While vacationing, Rosalie sees a mountain and its reflection on the still water of a lake. She draws the mountain and its refle
Greeley [361]

Answer:

I would say (2,-9) is her projection

6 0
1 year ago
There are 200 students in eleventh grade high school class. There are 40 students in the soccer team and 50 students in the bask
bekas [8.4K]

Answer:

P(A) = 0.2

P(B) = 0.25

P(A&B) = 0.05

P(A|B) = 0.2

P(A|B) = P(A) = 0.2

Step-by-step explanation:

P(A) is the probability that the selected student plays soccer.

Then:

P(A)=\dfrac{40}{200}=0.2

P(B) is the probability that the selected student plays basketball.

Then:

P(B)=\dfrac{50}{200}=0.25

P(A and B) is the probability that the selected student plays soccer and basketball:

P(A\&B)=\dfrac{10}{200}=0.05

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

P(A|B)=\dfrac{P(A\&B)}{P(B)}=\dfrac{10}{50}=0.2

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.

4 0
2 years ago
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