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Wewaii [24]
2 years ago
15

A spring stretches by 21.0 cm when a 135 n object is attached. what is the weight of a fish that would stretch the spring by 49

cm?
Mathematics
1 answer:
Akimi4 [234]2 years ago
8 0
If the stretch is proportional to the weight, it will satisfy
   weight/(49 cm) = (135 N)/(21 cm)
   weight = (49/21)×135 N
   weight = 315 N

The weight of the fish would be 315 N.
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The manager of a symphony in a large city wants to investigate music preferences for adults and students in the city. Let pA rep
monitta

Answer:

Answer E

Step-by-step explanation

The statement gives a probability of approximately 0.022 for the difference in sample proportions, pˆA−pˆS, being greater than 0.

6 0
1 year ago
For each exercise draw circle O with radius 12. Then draw radii OA and OB to form an angle with the measure named. Find the leng
guajiro [1.7K]
<span>You are asked to draw circle O with radius 12. Then draw radii OA and OB to form an angle with the measure named. You are asked to find the length of AB. The answers for each of the following measures are:
1)Measure of AOB=90, AB = 16.97 units
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5 0
2 years ago
The local pizza shop sells several special items.
Anna35 [415]

Answer:

Tax for Italian Salad=$0.20

Tax for Lasagna= $0.43

Tax for  Spaghetti =$0.21

Tax for Fettuccini Alfredo   =$0.36

Step-by-step explanation:

Hi, to answer this question we have to multiple the price of each item by the tax percentage in decimal form (divided by 100):

Italian Salad =$3.99  

  • Tax for Italian Salad= 3.99 x (5/100) = 3.99 x 0.05 =$0.20

Lasagna =$8.50  

  • Tax for Lasagna= 8.50 x (5/100) = 8.50 x 0.05 =$0.43

Spaghetti =$4.29  

  • Tax for Spaghetti = 4.29x (5/100) = 4.29 x 0.05 =$0.21

Fettuccini Alfredo =$7.17

  • Tax for Fettuccini Alfredo = 7.17 x (5/100) = 7.17 x 0.05 =$0.36

Feel free to ask for more if needed or if you did not understand something.  

6 0
2 years ago
Read 2 more answers
Find the value of cosAcos2Acos3A...........cos998Acos999A where A=2π/1999
Lady bird [3.3K]
Hello,

Here is the demonstration in the book Person Guide to Mathematic by Khattar Dinesh.

Let's assume
P=cos(a)*cos(2a)*cos(3a)*....*cos(998a)*cos(999a)
Q=sin(a)*sin(2a)*sin(3a)*....*sin(998a)*sin(999a)

As sin x *cos x=sin (2x) /2

P*Q=1/2*sin(2a)*1/2sin(4a)*1/2*sin(6a)*....
         *1/2* sin(2*998a)*1/2*sin(2*999a) (there are 999 factors)
= 1/(2^999) * sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
 as sin(x)=-sin(2pi-x) and 2pi=1999a

sin(1000a)=-sin(2pi-1000a)=-sin(1999a-1000a)=-sin(999a)
sin(1002a)=-sin(2pi-1002a)=-sin(1999a-1002a)=-sin(997a)
...
sin(1996a)=-sin(2pi-1996a)=-sin(1999a-1996a)=-sin(3a)
sin(1998a)=-sin(2pi-1998a)=-sin(1999a-1998a)=-sin(a)

So  sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
= sin(a)*sin(2a)*sin(3a)*....*sin(998)*sin(999) since there are 500 sign "-".

Thus
P*Q=1/2^999*Q or Q!=0 then
P=1/(2^999)

       








7 0
1 year ago
Read 2 more answers
Given that tangent theta = negative 1, what is the value of secant theta, for StartFraction 3 pi Over 2 EndFraction less-than th
Rashid [163]

Answer:

sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}

Step-by-step explanation:

Start by noticing that the angle \theta is on the 4th quadrant (between \frac{3\pi}{2} and 2\pi. Recall then that in this quadrant the functions tangent and cosine are positive, while the function sine is negative in value. This is important to remember given the fact that tangent of an angle is defined as the quotient of the sine function at that angle divided by the cosine of the same angle:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Now, let's use the information that the tangent of the angle in question equals "-1", and understand what that angle could be:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-1=\frac{sin(\theta)}{cos(\theta)}\\-cos(\theta)=sin(\theta)

The particular special angle that satisfies this (the magnitude of sine and cosine the same) in the 4th quadrant, is the angle \frac{7\pi}{4}

which renders for the cosine function the value \frac{\sqrt{2} }{2}.

Now, since we are asked to find the value of the secant of this angle, we need to remember the expression for the secant function in terms of other trig functions: sec(\theta)=\frac{1}{cos(\theta)}

Therefore the value of the secant of this angle would be the reciprocal of the cosine of the angle, that is: sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}

6 0
1 year ago
Read 2 more answers
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