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Wewaii [24]
2 years ago
15

A spring stretches by 21.0 cm when a 135 n object is attached. what is the weight of a fish that would stretch the spring by 49

cm?
Mathematics
1 answer:
Akimi4 [234]2 years ago
8 0
If the stretch is proportional to the weight, it will satisfy
   weight/(49 cm) = (135 N)/(21 cm)
   weight = (49/21)×135 N
   weight = 315 N

The weight of the fish would be 315 N.
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Suppose c and d vary inversely, and d = 2 when c = 17.
balu736 [363]

Answer:

c = 34/d

d = 1/2

Step-by-step explanation:

Part A

Basic Formula

c = k/d

17 = k/2         Multiply both sides by 2

17*2 = k*2/2     Combine

34 = k

So the equation is c = 34/d

Part B

c = 68

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d = ?

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d = 34/68                Simplify

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2 years ago
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nikklg [1K]
For rectangle
l=3.07m
b=2.24m
so longest side that can be drawn is diagonal of rectangular board
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The foundation of a building is in the shape of a rectangle, with a length of 20 meters (m) and a width of 18 m. To the nearest
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Answer:

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(5,1)

substitute

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