<span>A = 2 * (0.5ab) + b (10 - a) = ab + 10b - ab = 10b
10b = 30√2; b = 3√2
sin α = 3√2 / 6; α = 45 degrees
Small angle: 45°; Large angle: 135°</span><span>
</span>
Answer:
y2= 2x-4
y3=6x-1
y4= x-1
y5=2x
Step-by-step explanation:
for y=2x-1
1) for a vertical translation down of 3 units
y2= y-3 =(2x-1)-3= 2x-4
y2= 2x-4
2) for a slope increased by 4
y3= y+ 4x = 2x-1 +4x = 6x-1
y3=6x-1
3) for sloped divided in half. slope of y : m=2 → slope of y4=2/2 =1
y4= x-1
4) shifted up (vertical translation) of 1 unit
y5= y+1 = 2x-1+1=2x
y5=2x
Answer:
80 minutes or 1 h 20 minutes
Step-by-step explanation:
15-13=2
2/0.025=80
So we can conclude that it takes 80 minutes till it reaches 13 feet.
<span>The number of dollars collected can be modelled by both a linear model and an exponential model.
To calculate the number of dollars to be calculated on the 6th day based on a linear model, we recall that the formula for the equation of a line is given by (y - y1) / (x - x1) = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (3, 8)
The equation of the line representing the model = (y - 2) / (x - 1) = (8 - 2) / (3 - 1) = 6 / 2 = 3
y - 2 = 3(x - 1) = 3x - 3
y = 3x - 3 + 2 = 3x - 1
Therefore, the amount of dollars to be collected on the 6th day based on the linear model is given by y = 3(6) - 1 = 18 - 1 = $17
To calculate the number of dollars to be calculated on the 6th day based on an exponential model, we recall that the formula for exponential growth is given by y = ar^(x-1), where y is the number of dollars collected and x represent each collection day and a is the amount collected on the first day = $2.
8 = 2r^(3 - 1) = 2r^2
r^2 = 8/2 = 4
r = sqrt(4) = 2
Therefore, the amount of dollars to be collected on the 6th day based on the exponential model is given by y = 2(2)^(5 - 1) = 2(2)^4 = 2(16) = $32</span>
Answer:
Total amount of water = 5,200,000
Step-by-step explanation:
Given:
water produced = 50,000 quarts of water per week
Production drop = 5% = 0.05 per year
Number of week in year = 52 week
Find:
Total amount of water
Computation:
Sum = a / r
a = 50,000 x 52
a = 2,600,000
Sum = a / [1-r]
Sum = 2,600,000 / 5%
Sum = 2,600,000 / 0.05
Total amount of water = 5,200,000
