Answer: 0.9332.
Step-by-step explanation:
Claim : College Algebra final exam score of engineering majors equal to 88.
Given that : The test statistic is z equals to 1.50.
To find the p-value (Probability value), we use standard normal distribution table, and search the p-value corresponds to the z-score.
In a Standard Normal Distribution Table below, the p-value corresponds z equals 1.5 is 0.9332.
Hence, the p-value is 0.9332.
Answer:
30,000,000
Step-by-step explanation:
You are given the number 8,531,980,112.45.
Look at attached place value chart.
If we go to the left from decimal point, then we have
Digit 3 in the number 8,5 <u>3</u> 1,980,112.45 is on ten millions position, so the value of this digit is 30,000,000
Answer:
The general equation of a circle is x² + y² - 6x - 16y + 48 = 0 .
Step-by-step explanation:
The standard form of equation of circle.
Where (h,k) is the centre of a circle and r is the radius.
As given
The center of a circle is located at (3, 8), and the circle has a radius that is 5 units .
Put in the formula
(By using the formula (a - b)² = a² + b²- 2ab)
As 5² = 25
x² + 9 - 6x + y² + 64 - 16y = 25
x² + y² - 6x - 16y + 9 + 64 = 25
x² + y² - 6x - 16y + 73 = 25
x² + y² - 6x - 16y + 73 - 25 = 0
x² + y² - 6x - 16y + 73 - 25 = 0
x² + y² - 6x - 16y + 48 = 0
(As the general equation of a circle are in the form x² + y² + Ax +By + F =0 Where A,B and C are constant .)
Therefore the general equation of a circle is x² + y² - 6x - 16y + 48 = 0 .
Answer:
95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].
Step-by-step explanation:
We are given that a pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome).
In the first stages of a clinical trial, it was successful for 7 out of the 14 women.
Firstly, the pivotal quantity for 95% confidence interval for the true proportion is given by;
P.Q. = ~ N(0,1)
where, = sample proportion of women who find success with this new treatment =
= 0.50
n = sample of women = 14
<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>
So, 95% confidence interval for the true proportion, p is ;
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%
level of significance are -1.96 & 1.96}
P(-1.96 < < 1.96) = 0.95
P( <
<
) = 0.95
P( < p <
) = 0.95
<u />
<u>95% confidence interval for p</u> = [ ,
]
= [ ,
]
= [0.238 , 0.762]
Therefore, 95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].