Ask question

Ask question

All categories

2 years ago

10

Nia plans to put enough money in the bank each week for 100 weeks so that the amount in the bank is always proportional to the w

eek number. On week 8, she had $20.00. On week 12, she had $30.00. How much money will be in the savings account on week 100?
$40
$66
$225
$250

2 answers:

dimaraw [331]2 years ago

7 0

250 in savings account

kobusy [5.1K]2 years ago

6 0

Nia will have $250 in the savings account

You might be interested in

In the diagram, AC=BD=17 and BC=3. The length of segment AD is

Anastaziya [24]

The length of ad would also have to be the three also. This is logically because ac and bd would be the two going across making them equal. This meaning to connect the lines together if they were parallel bc and ad lengths would be equivalent.

7 0

2 years ago

Marcelo played a carnival game at the Interstate Fair 6 times. He spent 3 tokens to play each game, and he won 7 tokens each gam

atroni [7]

Hhiiiiiiiiiiiiiiiiiiiiiiiiiiiii

6 0

1 year ago

The heights of 200 adults were recorded and divided into two categories. Which two-way frequency table correctly shows the margi

Temka [501]

Answer: c

Step-by-step explanation:

C

7 0

2 years ago

-6/5-2/5v+4/15+1/3v please help

PtichkaEL [24]

Answer:

-14/15-1/15v

Step-by-step explanation:

First you make all of the fractions have the common denominator 15.

And then you have -18/15-6/15v+4/15+5/15v

Then you combine like terms to get -14/15-1/15v

5 0

2 years ago

A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip. On the return route, the boat trav

Georgia [21]

<em><u>The intervals included in solution are:</u></em>

$\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0$

<em><u>Solution:</u></em>

Given that,

A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip

On the return route, the boat travels against the current, decreasing the boat's rate by 10 mph

The group needs to travel an average of at least 24 mph

<em><u>Given inequality is:</u></em>

$\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}$

<em><u>We have to solve the inequality</u></em>

$\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}\\\\\frac{2}{x} - 10\geq \frac{2}{24}$

$\mathrm{Subtract\:}\frac{2}{24}\mathrm{\:from\:both\:sides}\\\\\frac{2}{x}-10-\frac{2}{24}\ge \frac{2}{24}-\frac{2}{24}\\\\Simplify\\\\\frac{2}{x}-10-\frac{2}{24}\ge \:0$

$\frac{2}{x}-\frac{10}{1}-\frac{2}{24} \geq 0\\\\\frac{ 2 \times 24}{x \times 24} -\frac{10 \times 24}{1 \times 24} - \frac{2 \times x }{24 \times x}\geq 0\\\\\frac{48}{24x}-\frac{240x}{24x}-\frac{2x}{24x}\geq 0\\\\Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions\\\\\frac{48-240x-2x}{24x}\geq 0\\\\Add\:similar\:elements\\\\\frac{48-242x}{24x}\ge \:0$

$\mathrm{Multiply\:both\:sides\:by\:}24\\\\\frac{24\left(48-242x\right)}{24x}\ge \:0\cdot \:24\\\\Simplify\\\\\frac{48-242x}{x}\ge \:0\\\\Factor\ common\ terms\\\\\frac{-2\left(121x-24\right)}{x}\ge \:0\\\\\mathrm{Multiply\:both\:sides\:by\:}-1\mathrm{\:\left(reverse\:the\:inequality\right)}$

When we multiply or divide both sides by negative number, then we must flip the inequality sign

$\frac{\left(-2\left(121x-24\right)\right)\left(-1\right)}{x}\le \:0\cdot \left(-1\right)\\\\\frac{2\left(121x-24\right)}{x}\le \:0\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{\frac{2\left(121x-24\right)}{x}}{2}\le \frac{0}{2}\\\\Simplify\\\\\frac{121x-24}{x}\le \:0$

$\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{121x-24}{x}\\$

This is attached as figure below

From the attached table,

$\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0\\\\0$

<em><u>Therefore, solution set is given as</u></em>:

$\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0$

8 0

2 years ago

Read 2 more answers