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jarptica [38.1K]
2 years ago
14

Efectuati impartirea 12xy:3x

Mathematics
2 answers:
adelina 88 [10]2 years ago
7 0

In this question , we have to simplify the given ratio, which is

12xy:3x

First we have to see which factor is common in numerator and denominator,

We can write 12 as 3 times 4, that is

3*4x*y :3x

So the common factor is 3x.

In the next step, we cancel out 3x

4y:1

And that's the required simplified form .

devlian [24]2 years ago
4 0
Divide the 3 and 12 to get 4 then add the xes to get 4x2y
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Kirima is building a wall for her snow fort. She first makes a firm base out of snow, and then piles uniformly sized blocks of s
MrMuchimi

Answer:

The correct option is;

0.4 represents the height of each block

Step-by-step explanation:

The information given are;

Kirima first builds a firm base of a given height

Kirima is building her wall using uniformly sized bricks

the height of the wall she is building depends on the number of blocks stacked to form the wall

Therefore, variable that depends on other variable, which is the dependent variable, y, is the height of the wall

The independent, which determines the value of the dependent variable is the number of blocks added, x

The gradient of the equation is the height of each block = 0.4

The y-intercept is the starting value, which is the firm base of dimension, 0.6

Therefore, 0.4 represents the height of each block.

7 0
2 years ago
A circle has a radius of 5ft and an arc of length 7 ft is made by the intersection of the circle with a central angle. Which equ
Serggg [28]

Answer:

\frac{q}{360} × π10 = 7

Explanation:

The formula to find arc length is \frac{x}{360} × \pi r^{2}

Simply plug in radius and arc length to get your equation.

5 0
2 years ago
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70.18 divided by 0.9 round the answer to the nearest hundredth
storchak [24]

Answer:

77.98

Step-by-step explanation:

4 0
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Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

8 0
2 years ago
For which pairs of functions is (f circle g) (x)?
iVinArrow [24]

Answer:

I just took the test and aint gon cap i guessed on it but the answer is B.

f(c)=2/x and g(x)=2/x

sorry I late but i thought i should still tell

Step-by-step explanation:

4 0
2 years ago
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