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2 years ago

Efectuati impartirea 12xy:3x

Mathematics

2 answers:

adelina 88 [10]2 years ago

7 0

In this question , we have to simplify the given ratio, which is

12xy:3x

First we have to see which factor is common in numerator and denominator,

We can write 12 as 3 times 4, that is

$3*4x*y :3x$

So the common factor is 3x.

In the next step, we cancel out 3x

$4y:1$

And that's the required simplified form .

devlian [24]2 years ago

4 0

Divide the 3 and 12 to get 4 then add the xes to get 4x2y

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Determine the value of (tangent of 88 degrees, 22 minutes, and 45 seconds). In this case, minutes are 1/60 of a degree and secon

mariarad [96]

Answer:

c. 35.34015106

Step-by-step explanation:

As with many problems of this nature, you only need to get close to be able to choose the correct answer. 22 minutes 45 seconds is just slightly less than 1/2 degree (30 minutes), so the tangent value will be just slightly less than tan(88.5°) ≈ 38. The appropriate choice is 35.34015106.

If you need confirmation, you can find tan(88°) ≈ 29, so you know the answer will be between 29 and 38.

The above has to do with strategies for choosing answers on multiple-choice problems. Below, we will work the problem.

The angle is (in degrees) ...

88 + 22/60 +45/3600 = 88 + (22·60 +45)/3600 = 88 +1365/3600

≈ 88.3791666... (repeating) . . . . degrees

A calculator tells you the tangent of that is ...

tan(88.3791666...°) ≈ 35.3401510614

Many calculators will round that to 10 digits, as in the answer above. Others can give a value correct to 32 digits. Spreadsheet values will often be correct to 15 or 16 digits.

4 0

2 years ago

Compute the integral (a) int sin (pi x) dx by letting u = pi x. (b) int e^(x/2) dx by letting u = x/2. Show that you got the cor

Maslowich

Answer:

(a) $\int sin(\pi x) dx$ $=-\frac {cos \pi x}{\pi}+c$

(b) $\int e^\frac{x}{2} dx$ $=2e^\frac{x}{2}+c$

Step-by-step explanation:

(a)

$\int sin(\pi x) dx$

Let u = π x

differentiating with respect to x

du = π dx

$\Rightarrow dx=\frac{du}{\pi}$

Putting the value of x and dx

$=\int sin u \frac{du}{\pi}$

$=\frac{-cos u}{\pi}+c$ [ c is an arbitrary constant]

Now putting the value of u

$=-\frac {cos \pi x}{\pi}+c$

(b)

$\int e^\frac{x}{2} dx$

Let $u=\frac{x}{2}$

differentiating with respect to x

$du= \frac{1}{2} dx$

2du = dx

Putting the value of x and dx

= $\int e^u.2.du$

= $2e^u +c$

Now putting the value of u

$=2e^\frac{x}{2}+c$ [ c is an arbitrary constant]

3 0

2 years ago

Explain how your work your knowledge of place value helps you divide a number in thousands by whole numbers to 10 give a example

Anna71 [15]

Place value is the value each digit has in its position: in order from higher to lower value, there is thousands, hundreds, tens, and ones.
When you divide by 10, you are moving (only once) every digit from its present place value to the right.
For example 6430 : 10= 643, you have moved every digit to the right, making the zero disappear (or better yet, separated by a hidden and in this case useless comma).

3 0

2 years ago

Which statement justifies that 3x2 − 2x − 4 multiplied by 2x2 + x − 3 obeys the closure property of multiplication? The result 6

zalisa [80]

We have been given two polynomials $3x^2-2x -4 \text{ and } 2x^2+x-3$

Let us first multiply these polynomials.

$(3x^2 - 2x - 4)(2x^2 + x - 3)\\
\\
=3x^2(2x^2 + x - 3) -2x(2x^2 + x - 3)-4(2x^2 + x - 3)\\
\\
=6 x^4 - x^3 - 19 x^2 + 2 x + 12$

Now, we know that polynomials follows closure property of multiplication.

It means that when we multiply two polynomials, the result will be a polynomial.

Since, when we multiplied the given polynomials, we got $6 x^4 - x^3 - 19 x^2 + 2 x + 12$ which is a polynomial.

Therefore, the correct option is

The result $6 x^4 - x^3 - 19 x^2 + 2 x + 12$ is a polynomial.

4 0

2 years ago

In the problems below, f(x) = log₂x and

kramer

Answer:

(1,0)

Step-by-step explanation:

The given functions are:

f(x) = log₂x

and

g(x) = log₁₀x

We know that logarithm of 1 is always zero.

This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1

Therefore the point the graphs of f and g have in common is (1,0)

3 0

1 year ago