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jarptica [38.1K]

2 years ago

14

Efectuati impartirea 12xy:3x

2 answers:

adelina 88 [10]2 years ago

7 0

In this question , we have to simplify the given ratio, which is

12xy:3x

First we have to see which factor is common in numerator and denominator,

We can write 12 as 3 times 4, that is

$3*4x*y :3x$

So the common factor is 3x.

In the next step, we cancel out 3x

$4y:1$

And that's the required simplified form .

devlian [24]2 years ago

4 0

Divide the 3 and 12 to get 4 then add the xes to get 4x2y

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1 year ago

Which graph represents a linear function? A coordinate plane is shown with a way line beginning along the x axis and continuing

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2 years ago

Read 2 more answers

Lou started his savings account with 50$ he now only has 31$. What percent of change did his savings account have?

vladimir1956 [14]

Answer:

Step-by-step explanation:

50 - 31 = 19

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4 0

1 year ago

A project’s critical path is composed of activities A (variance .33), B (variance .67), C (variance .33), and D (variance .17).

julia-pushkina [17]

Answer:

The standard deviation on the critical path = 0.834

Step-by-step explanation:

Variance of activity A ( $V_{1}$ ) = 0.33

Variance of activity B ( $V_{2}$ ) = 0.67

Variance of activity C ( $V_{3}$ ) = 0.33

Variance of activity D ( $V_{4}$ ) = 0.17

Thus the standard deviation on the critical path ( $\alpha ^{2}$ ) = $V_{1} ^{2}$ + $V^2_{2}$ + $V^2_{3}$ + $V^2_{4}$

$\alpha ^{2}$ = $0.33^{2}$ + $0.67^{2}$ + $0.33^{2}$ + $0.17^{2}$

$\alpha ^{2}$ = 0.6956

$\alpha$ = 0.834

The standard deviation on the critical path = 0.834

4 0

2 years ago

After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum

Svetlanka [38]

Answer: 40000

Step-by-step explanation:

The formula to find the sample size is given by :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$ , where p is the prior estimate of the population proportion.

Here we can see that the sample size is inversely proportion withe square of margin of error.

i.e. $n\ \alpha\ \dfrac{1}{E^2}$

By the equation inverse variation, we have

$n_1E_1^2=n_2E_2^2$

Given : $E_1=0.05$ $n_1=1000$

$E_2=0.025$

Then, we have

$(1000)(0.05)^2=n_2(0.025)^2\\\\\Rightarrow\ 2.5=0.000625n_2\\\\\Rightarrow\ n_2=\dfrac{2.5}{0.000625}=4000$

Hence, the sample size will now have to be 4000.

6 0

2 years ago