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shutvik [7]
2 years ago
15

Sally's Stuffed Animal Company charges $0.75 per pound to ship stuffed animals. Part A: Write an equation to determine the total

cost, c, to ship p pounds of stuffed animals. Use your equation to determine the cost of shipping 2 pounds of stuffed animals. (6 points) Part B: If the company reduces the cost to ship the stuffed animals by 0.05 per pound, write an equation to determine the total cost, c, to ship p pounds of stuffed animals with the reduced cost. (4 points)
Mathematics
1 answer:
zalisa [80]2 years ago
6 0
Hope this helps but I think it might be:
Part A: c=0.75p
the cost of shipping for 2 pounds
c=0.75p
c=0.75*2
c=$1.50
Part B: c=0.05p
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The closest answer that I could find would be (-2, 2). The answer to the system is (-1.4, 1.6)

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The closing price (in dollars) per share of stock of tempco electronics on the tth day it was traded is approximated by p(t) = 2
Vaselesa [24]

solution:

The closing price (in dollars) per share of stock of Tempco Electronics on the tth day it was  

traded is approximated by  

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15 (0 ≤ t ≤ 24)  

where t = 0 corresponds to the time the stock was first listed on a major stock exchange.  

What was the rate of change of the stock's price at the close of the 15th day of trading?  

P'(t) = 12(cos πt/30) - 6 (cos πt/15) + 4(cos πt/10) - 3(cos 2πt/15)  

t = 15  

P'(t) = 12(cos 15π/30) - 6 (cos 15π/15) + 4(cos 15π/10) - 3(cos 30π/15)  

P'(t) = 12(cos π/2) - 6 (cos π) + 4(cos 3π/2) - 3(cos 2π)  

P'(t) = 12(0) - 6(-1) + 4(0) - 3(1) = 6 - 3  

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the closing price on that day

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15  

t = 15  

P(t) = 20 + 12 sin 15π/30 − 6 sin 15π/15 + 4 sin 15π/10 − 3 sin 30πt/15  

P(t) = 20 + 12 sin π/2 − 6 sin π + 4 sin 3π/2 − 3 sin 2π  

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4 0
2 years ago
A random sample of 25 roundtrip flights between Philadelphia and Dallas has an average airfare of $393.50 with a sample standard
Sauron [17]

Answer:

$393.50+/-$19.72

= ( $373.78, $413.22)

Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $393.50

Standard deviation r = $50.30

Number of samples n = 25

Confidence interval = 95%

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Substituting the values we have;

$393.50+/-1.96($50.30/√25)

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$393.50+/-$19.7176

$393.50+/-$19.72

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Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)

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2 years ago
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Answer:

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Step-by-step explanation:

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