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2 years ago

5

barnaby has 288 counters in a bag. the counters are red yellow and white. 3/8 of the counters are yellow and white in the ratio

of 1:4. work out how many counters of each colour there are.

1 answer:

postnew [5]2 years ago

8 0

Answer:

idk

Step-by-step explanation:

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Sandra wants to rent a car to take a trip and has a budget of $90. There is a fixed rental fee of $30 and a daily fee of $10. Wr

nikdorinn [45]

Option B is the correct answer

Step-by-step explanation:

Step 1 :

Given,

Maximum budget Sandra has for the trip is $90

Fixed rental fee = $30

Daily fee = $10

Step 2 :

Let x be the number of the days for which Sandra can go for the trip

If the daily fee is $10, the cost for x number of days would be 10*x

the fixed fee is $30

So the equation is represent the cost of the trip is 30 + 10 x

given that the maximum budget is $90, the above cost should always be less $90

So the required inequality is 30 + 10x ≤ 90

Option B is the correct answer

4 0

1 year ago

The m6 = (11x + 8)° and m7 = (12x – 4)° What is the measure of 4? m4 = 40° m4 = 48° m4 = 132° m4 = 140°

bezimeni [28]

M< 6 = m< 7 (vertical angles)
11x + 8 = <span>12x – 4
12x - 11x = 8 + 4
x = 12
so
m< 6 = </span>11x + 8
m< 6 = 11(12) + 8
m< 6 = 132 + 8
m< 6 = 140

m<4 = 180 - m<6
m<4 = 180 - 140
m<4 = 40

answer

<span>m<4 = 40</span>

7 0

2 years ago

Read 2 more answers

Which expression is equivalent to x Superscript negative five-thirds? StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot

Anastasy [175]

Option B : $\frac{1}{\sqrt[3]{x^{5} } }$ is the expression equivalent to $x^{-\frac{5}{3}$

Explanation:

The given expression is $x^{-\frac{5}{3}$

Rewriting the expression $x^{-\frac{5}{3}$ using the exponent rule, $a^{-b}=\frac{1}{a^{b}}$

Hence, we get,

$\frac{1}{x^{\frac{5}{3} } }$

Simplifying, we get,

$\frac{1}{\left(x^{5}\right)^{\frac{1}{3}}}$

Applying the rule, $a^{\frac{1}{n}}=\sqrt[n]{a}$

Thus, we have,

$\frac{1}{\sqrt[3]{x^{5} } }$

Now, we shall determine from the options that which expression is equivalent to $x^{-\frac{5}{3}$

Option A: $\frac{1}{\sqrt[5]{x^{3} } }$

The expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option A is not the correct answer.

Option B: $\frac{1}{\sqrt[3]{x^{5} } }$

The expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to $x^{-\frac{5}{3}$

Hence, Option B is the correct answer.

Option C: $-\sqrt[3]{x^5}$

The expression $-\sqrt[3]{x^5}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[3]{x^5}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option C is not the correct answer.

Option D: $-\sqrt[5]{x^3}$

The expression $-\sqrt[5]{x^3}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[5]{x^3}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option D is not the correct answer.

4 0

1 year ago

Read 2 more answers

The length of a rectangle is 4n, and twice as long as the width. the perimeter pf the rectangle is twice as long as that of an e

sattari [20]

2n,perimeter of rectangle is 12n ( width is 2n because length is twice of the width)
1/2 of that ( because the perimeter of the rectangle is twice of the equilateral triangle) is 6n. Since its an equilateral triangle, divide 6n by 3 to get 2n

7 0

1 year ago

Round 4.265 to the nearest hundredth

jekas [21]

4.265 rounded to the nearest hundredth is 4.27

3 0

1 year ago