1 year ago

For this problem, use the tables and charts shown in this section. (Use picture provided)

Mathematics

2 answers:

klemol [59]1 year ago

5 0

I’m eye billing it I would say $300 bekuz the rest are to low loll

mojhsa [17]1 year ago

5 0

Answer:

Step-by-step explanation:

0 because there is a $100 duty free exemption.

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Weiming, Farhan and Sam had some comic books.

mixas84 [53]

Answer:

Farhan had 9 comic books

Sam had 51 comic books and lived in his Mother's basement

Step-by-step explanation:

W + F = 36

W = 3F

3F + F = 36

F = 9

W = 27

S + F = 60

S + 9 = 60

S = 51

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1 year ago

For a few months, Dexter recorded the amounts, in fluid ounces, of laundry detergent remaining y after he and his family washed

BigorU [14]

Definitely it's B: The amt of detergent left after x loads have been washed is y = (-$1.60/load)x + 50.

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1 year ago

Maria sets a goal of jogging 17.5miles this week. She plans on running 2.75 miles each day for 7 days . If she follows her plan

vovangra [49]

Yes, he will get 19.25 miles.

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1 year ago

Read 2 more answers

Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skat

BartSMP [9]

Let x be a random variable representing the number of skateboards produced
a.) P(x ≤ 20,555) = P(z ≤ (20,555 - 20,500)/55) = P(z ≤ 1) = 0.84134 = 84.1%

b.) P(x ≥ 20,610) = P(z ≥ (20,610 - 20,500)/55) = P(z ≥ 2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275 = 2.3%

c.) P(x ≤ 20,445) = P(z ≤ (20,445 - 20,500)/55) = P(z ≤ -1) = 1 - P(z ≤ 1) = 1 - 0.84134 = 0.15866 = 15.9%

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2 years ago

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than

aleksandrvk [35]

Answer:

The alternative hypothesis being tested in this example is that the tire life is of more than 60,000 miles, that is:

$H_1: \mu > 60,000$

Step-by-step explanation:

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than 60,000 miles.

At the null hypothesis, we test if the tire life is of at most 60,000 miles, that is:

$H_0: \mu \leq 60,000$

At the alternative hypothesis, we test if the tire life is of more than 60,000 miles, that is:

$H_1: \mu > 60,000$

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2 years ago