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djverab [1.8K]
1 year ago
5

Frederick designed an experiment in which he spun a spinner 20 times and recorded the results of each spin.He spun a 4 five time

s. Which statements are true? Choose all that apply.
A.For the experimental outcomes to be closer to the predicted outcome, the number of trials should be increased.
B.For the experimental outcomes to be closer to the predicted outcome, the number of trials should be decreased.
C.If the number of trials is changed, the experimental probability also changes.
D.If the number of trials is changed, the theoretical probability also changes.
E.If the number of trials is changed, the number of experimental outcomes also changes.

Mathematics
1 answer:
kogti [31]1 year ago
6 0
If the number of trials is changed the number of experimental outcomes also changes
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1. The speed at which an automated assembly line produces a product follows a normal distribution with mean production time of 3
strojnjashka [21]

Answer: Probability = 0.2

Step-by-step explanation:

Given data:

Mean production time = 32.20 seconds

Standard deviation = 1,05seconds

probability that a full production run will take less than 32 seconds on average to produce

= P(Xbar<32)

= P(Z<-0.8518)

= 0.2

8 0
1 year ago
Sue wants to paint the longest wall in her bedroom pink. she measured the wall and found that it is 10 feet long and 8 feet tall
jekas [21]

Answer:

Sue should buy 1.6 quart of paint.

Step-by-step explanation:

First we need to find out the area of longest wall

Area =length × breadth

Area= 10 × 8 = 80 square feet

To cover 50 square feet we have required 1 quart of paint

So for covering 1 square feet we have required 1/50 quart of paint

So for covering 80 square feet we have required  ( 1×80 ) / 50 quart

= 1.6 quart of paint

6 0
2 years ago
The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a
maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}

\text{P(green swordtail)}=\dfrac{80}{140}

\text{P(green swordtail)}=\dfrac{4}{7}

Therefore, the probability that the selected fish is a green swordtail is \dfrac{4}{7}.

B.  We have to find the probability that the selected fish is male.

\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}

\text{P(Male fish)}=\dfrac{36+24}{140}

\text{P(Male fish)}=\dfrac{60}{140}

\text{P(Male fish)}=\dfrac{3}{7}

Therefore, the probability that the selected fish is a male, is \dfrac{3}{7}.

C. We have to find the probability that the selected fish is a male green swordtail.

\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}

\text{P(Male green swordtail)}=\dfrac{36}{140}

\text{P(Male green swordtail)}=\dfrac{9}{35}

Therefore, probability that the selected fish is a male green swordtail is \dfrac{9}{35}.

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}

\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}

\text{P(Male or green swordtail)}=\dfrac{96}{140}

\text{P(Male or green swordtail)}=\dfrac{24}{35}

Therefore, the probability the selected fish is either a male or a green swordtail is \dfrac{24}{35}.

4 0
2 years ago
A juice drink filling machine, when in perfect adjustment, fills the bottles with 12 ounces of drink on an average. Any overfill
ozzi

Answer:

d. The average is equal to 12 ounces.

Step-by-step explanation:

In this problem, the drink filling machine must be perfectly calibrated at 12 ounces since it needs to be shut down in cases of overfilling (mean > 12 ounces) and underfilling (mean < 12 ounces). Therefore, the correct approach would be to test if the mean is 12 ounces and the correct set of hypothesis would be:

H_0:\mu=12\\H_a:\mu\neq 12

The correct alternative is d. The average is equal to 12 ounces.

5 0
2 years ago
Susan keeps track of the number of tickets sold for each play presented at the community theater. within how many standard devia
Citrus2011 [14]
The Mean = (135 + 71 + 69 + 80 + 158 + 152 + 161 + 96 + 122 + 118 + 87 + 85 ) : 12 = 111.166
The smallest value : 69
The greatest value : 161
s² = ∑( x i - x )² / ( n - 1 )
s² = ( 568.274 + 1613.3 + 1777.97 + 971.32 + 2193.42 + 1667.4 + +2483.42 + 230 + 117.38 + 46.7 + 584 + 684.66 )  : 11
s² = 1176.1676
s = √s² = √1176.1676
s ( Standard deviation ) = 34.295
All the values fall within 2 standard deviations:
 x (Mean) - 2 s and  x + 2 s 
 
3 0
1 year ago
Read 2 more answers
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