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Papessa [141]
1 year ago
5

A flea treatment last 4 weeks. Jim's dog had to be treated every 3 weeks. How many weeks of flea treatment would Jim's dog get i

f the treatments only lasted 3 weeks?
Mathematics
1 answer:
Reptile [31]1 year ago
6 0

Answer:

Number of weeks in a year = 52 weeks

If in a normal year when each package of flea treatment lasts for 4 weeks, then in a year there Jim's dog will have to be treated for

Where as, when the fleas are bad in a year, the treatment lasts for only 3 weeks.

Then in a year Jim's dog would get

So Jim's dog will get 17- 13 =4 treatments more.

4 treatments that are made in 3 weeks each will be 4×3 =12 weeks more treatment

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2 years ago
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The sum of two numbers is 90. The larger number is 14 more than 3 times the smaller number. Find the numbers
e-lub [12.9K]

Answer:

The numbers are 19 and 71.

Step-by-step explanation:

Let x and y represent the two numbers.  Then x + y = 90.  

Also, if we assume that the larger number is y, then y = 3x + 14.

We must solve this system of linear equations.  Since we already have the result of solution for y  (y = 3x + 14), let's use the substitution method to find the solution:

x + y = 90 becomes x + 3x + 14 = 90, or:

4x = 76.  Thus, x = 76/4, or 19.       If x = 19, then y = 3(19) + 14, or y = 71.

The numbers are 19 and 71.

Note that these add up to 90, as they must, and that 71 is 14 more than 3 times 19.

7 0
1 year ago
Felicia wanted to find the number of boys in the school band if 30% of the 50 students are boys. Is her answer correct? Explain
docker41 [41]

Answer:

Creo que con 15

Step-by-step explanation:

50 -------> 100%

X ---------> 30%

X = (50*30)/100

X= 15 boys

4 0
1 year ago
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Wheat contains about 2.5 kcal per gram, and the average U.S. male consumes 2500 kcal per day. How many hectares of wheat are nee
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2 years ago
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A metal alloy is a metal made by blending 2 or more types of metal. A jeweler has supplies of two metal alloys. On alloy is 30%
tensa zangetsu [6.8K]

Answer:

He should combine 1 kg of 30% alloy and 3 kg of 10% alloy.

Step-by-step explanation:

Let x = mass of 30% ally.

Let y = mass of 10% alloy.

He needs 4 kg of alloy, so the first equation, dealing with masses, is

x + y = 4

Now we deal with the amount of gold.

He uses x mass of 30% gold alloy. The amount of gold in that mass is 0.3x.

He uses y mass of 10% gold alloy. The amount of gold in that mass is 0.1y.

The total mass of gold is 0.3x + 0.1y. We are told the told the end alloy is 4 kg of 15% gold alloy. That contains 0.15(4) kg = 0.6 kg of gold.

The second equation is

0.3x + 0.1y = 0.6

Now we put together the two equations as a system of equations.

x + y = 4

0.3x + 0.1y = 0.6

Multiply both sides of the second equation by -10.

-3x - y = -6

Add this equation to the first original equation.

         x + y = 4

+     -3x - y = -6

---------------------

        -2x    = -2

            x    = 1

Now substitute x = 1 in the first original equation and solve for y.

x + y = 4

x + y = 4

y = 3

Answer: He should combine 1 kg of 30% alloy and 3 kg of 10% alloy.

6 0
2 years ago
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