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NNADVOKAT [17]
1 year ago
5

A toy rocket is launched from a platform 33 feet above the ground at a speed of 83 feet per second. The height of the rocket in

feet is given by the polynomial −16t2 + 83t + 33, where t is the time in seconds. How high will the rocket be after 3 seconds?
Mathematics
1 answer:
kiruha [24]1 year ago
4 0

Answer:

282ft

Step-by-step explanation:

83×3=249

249+33=282

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4 markers cost $7.04. Which equation would help determine the cost of 7 markers??
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Answer: 12.32

Step-by-step explanation:

7.04 divided by 4 = 1.76. 1.76 x 7 = 12.32.

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Find the solution to each of these recurrence relations and initial conditions. use an iterative approach such as that used in e
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2 years ago
Aubrey's dinner cost \$85$85dollar sign, 85. She tips the waitstaff 30\%30%30, percent for excellent service.
KATRIN_1 [288]
<h3><u>Question:</u></h3>

Aubrey's dinner cost $85 . She tips the waitstaff 30% for excellent service. How much does Aubrey tip the waitstaff?

<h3><u>Answer:</u></h3>

Aubrey paid $ 25.5 to the wait staff

<h3><u>Solution:</u></h3>

Given that, Aubrey's dinner cost $ 85

She tips the waitstaff 30% for excellent service

We have to find the amount paid as tip to wait staff

Cost = $ 85

Tip = 30 %

So the tip amount paid is 30 % of 85

<h3><u>Find out 30 % of 85</u></h3>

Tip\ Amount = 30 \% \times 85\\\\Tip\ Amount = \frac{30}{100} \times 85\\\\Tip\ Amount = 0.30 \times 85\\\\Tip\ Amount = 25.5

Thus Aubrey paid $ 25.5 to waitstaff

4 0
1 year ago
Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}

Dividing we get,

2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}

Adding, we have,

2 { h } 54 \text { min }=2.9 {h}

Thus, the total time taken by Joshua is 2.9 {h}

To determine the average speed we use the formula,

speed=\frac{distance}{time}

where distance=7250 and time=2.9

Hence, substituting the values we have,

speed=\frac{7250}{2.9}

Dividing, we get,

speed=2500

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0
2 years ago
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