Question

If trapezoid JKLM with vertices) (3, 4), K (6,4), L (8, 1) and M (1,1) is rotated 270 degrees counterclockwise, what are the

Answer 1

Answer:

$J' = (4,-3)$

Step-by-step explanation:

Given

$J = (3, 4)$

$K =(6,4)$

$L = (8, 1)$

$M = (1,1)$

$Rotation = 270CCW$

Required

Determine the new coordinate of J

From rules of rotation,

When a point (x,y) is rotated 270 degrees CCW;

The new point becomes (y,-x)

Considering point J

$J = (3, 4)$

This means

$(x,y) = (3,4)$

Where $x = 3$ and $y = 4$

Using the above rotation rule of

$(x,y) -> (y,-x)$

The coordinates of J' becomes

$J' = (4,-3)$