Suppose that we roll a fair die until a 6 comes up.

A local health care company wants to estimate the mean weekly elder day-care cost. A sample of 10 facilities shows a mean of $25

laiz [17]

Answer:

Step-by-step explanation:

Mean "X"=250

s = 25

n=10

Because Standard deviation is unknown and sample size is small, we must employ the T-distribution

df=n-1 = 10-1

df=9

For 90% confidence, t = 1.833

E=t*s/ $\sqrt{n\\$ = 1.833*(25/ $\sqrt{10}$ )

E=14.49

The 90% confidence interval is X±E=250±14.49 or 235.51, 264.49

8 0

1 year ago

HELP QUICK!

USPshnik [31]

Answer:

Eric will win if Nita chooses 7 and he chooses and number that is less than 17 (ex. n<17).

Nita will win if Eric chooses 17 and she chooses a number less than 8 (ex. n<8).

3 0

2 years ago

Please help me. The function g(x) is a transformation of f(x). If g(x) has a y-intercept at 3, which of the following functions

Step2247 [10]

<h3>Answer: D. g(x) = f(x)+4</h3>

The graph shows f(x) to have a y intercept at -1, which is where the diagonal line crosses the y axis. We want the y intercept to move to 3. So we must add 4 to the old y intercept to get the new y intercept.

We do this with every single point on f(x) to get g(x) = f(x)+4. This shifts the graph up 4 units.

8 0

1 year ago

Read 2 more answers

The angle \theta_1θ

enyata [817]

Answer:

$sin\theta_1 = \dfrac{\sqrt{217}}{19}$

Step-by-step explanation:

It is given that:

$cos\theta_1 = -\dfrac{12}{19}$

And we have to find the value of $sin\theta_1 = ?$

As per trigonometric identities, the relation between $sin\theta\ and \ cos\theta$ can represented as:

$sin^2\theta + cos^2\theta = 1$

Putting $\theta_1$ in place of $\theta$ Because we are given

$sin^2\theta_1 + cos^2\theta_1 = 1$

Putting value of cosine:

$cos\theta_1 = -\dfrac{12}{19}$

$sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}$

It is given that $\theta_1$ is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

$\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}$

8 0

1 year ago

In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegeta

alukav5142 [94]

Answer:

$Z_{0.05}=1.645$

Step-by-step explanation:

Given :In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegetables, and 458 reported that they preferred eating vegetables.

To Find :What value of z should be used to calculate a confidence interval with a 95 % confidence level?

Solution:

Confidence level = 95 % i.e.0.95

So, significance level = 5% i.e. 0.05

So, the value of z corresponding to significance level 0.05 should be used to calculate a confidence interval with a 95 % confidence level

So, $Z_{0.05}=1.645$

Hence z should be 1.645 to calculate a confidence interval with a 95 % confidence level.

4 0

1 year ago