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amid [387]
2 years ago
7

A sailor is looking at a kite. If he is looking at the kite at an angle of elevation of 36and the distance from the boat to the

point where the kite is directly overhead is 40 feet, how high is
the kite?

Mathematics
1 answer:
Nonamiya [84]2 years ago
7 0

Answer:

Height of the kite from the ground is 29.2 feet.

Step-by-step explanation:

For better explanation of the solution, see the figure attached :

The angle formed by the height of kite to that of the surface of the ground is right angle.

⇒ m∠ABC = 90°

Let angle of elevation be θ

Now, to find height of the kite : find length of AB

In right angled triangle ABC , using tan rule, we have\tan\theta=\frac{Perpendicular}{Base}\\\\\tan36^{\circ}=\frac{AB}{BC}\\\\\implies \tan36^{\circ}=\frac{AB}{40}\\\\\implies AB=0.73\times 40\\\\\bf\implies AB=29.2\thinspace{ feet}

Hence, Height of the kite from the ground is 29.2 feet.

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Match each three-dimensional figure to its volume based on the given dimensions. (Assume π = 3.14.)
LekaFEV [45]

Answer:

The volume of the cylinder is 150.72 cm³ ⇒ last answer

The volume of the cone is 314 cm³ ⇒ 1st answer

The volume of the pyramid is 160 cm³ ⇒ 2nd answer

The volume of the pyramid is 48 cm³ ⇒ 3rd answer

Step-by-step explanation:

* Lets revise the volumes of some shapes

- The volume of the cylinder of radius r and height h is:

 V = π r² h

- The volume of the cone of radius r and height h is:

 V = 1/3 π r² h

- The volume of the pyramid is:

 V = 1/3 × its base area × its height

* Lets solve the problem

# A cylinder with radius 4 cm and height 3 cm

∵ V = π r² h

∵ π = 3.14

∵ r = 4 cm , h = 3 cm

∴ v = 3.14 (4)² (3) = 150.72 cm³

* The volume of the cylinder is 150.72 cm³

# A cone with radius 5 cm and height 12 cm

∵ V = 1/3 π r² h

∵ π = 3.14

∵ r = 5 cm , h = 12 cm

∴ V = 1/3 (3.14) (5)² (12) = 314 cm³

* The volume of the cone is 314 cm³

# A pyramid with base area 16 cm² and height 30 cm

∵  V = 1/3 × its base area × its height

∵ The area of the base is 16 cm²

∵ The height = 30 cm

∴ V = 1/3 (16) (30) = 160 cm³

* The volume of the pyramid is 160 cm³

# A pyramid with square base of length 3 cm and height 16 cm

∵  V = 1/3 × its base area × its height

∵ The area of the square = s²

∵ The area of the base = 3² = 9 cm²

∵ The height = 16 cm

∴ V = 1/3 (9) (16) = 48 cm³

* The volume of the pyramid is 48 cm³

3 0
2 years ago
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A snack bar sells two types of gronala bars. An apricot bar costs $0.80, and a cranberry bar costs $1.25. write an algebraic exp
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Answer:

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Step-by-step explanation:

This equation has 2 variables. It also has 2 equations

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Carbon-141414 is an element that loses about 10\%10%10, percent of its mass every millennium (i.e., 100010001000 years). A sampl
ololo11 [35]

Answer:

Carbon-14 loses around 10% ( 0.1 in decimal form) of its mass, after one millennium.

Then if we start with a mass A of Carbon-14, after one millennium we will have a mass equal to:

A - A*0.1 = A*(0.9)

After another millennium, we will have a mass equal to:

A*(0.9) - A*(0.9)*0.1 = A*(0.9)^2

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We already can see the pattern here, after x millenniums, the mass of carbon-14 will be:

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Now, in this problem we have 600 grams of carbon-14, then the equation for the mass will be:

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4 0
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olya-2409 [2.1K]

Factorize the numerator as a difference of squares:

y^4-1=(y^2-1)(y^2+1)=(y-1)(y+1)(y^2+1)

Then if y\neq-1, the y+1 factors will cancel:

\dfrac{y^4-1}{y+1}=(y-1)(y^2+1)=y^3-y^2+y-1

so the answer is B.

8 0
2 years ago
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Katarina [22]

Answer:

( 4.8 ,7.6)

Step-by-step explanation:

We want to find the point, B(x,y) that divides the directed line segment from Messi, M(3,4) to S(6,10) in the ratio m:n=3:2

We use the section formula:

( \frac{mx_2+nx_1}{m + n} ,\frac{my_2+ny_1}{m + n})

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This gives us:

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6 0
2 years ago
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