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Anna007 [38]
2 years ago
5

A group of 10 students participate in chess club, karate club, or neither.

Mathematics
1 answer:
Afina-wow [57]2 years ago
8 1

Total number of students = 10

As we have to find

P(A/B) = Probability( A when B has happend)

P(A/B)= P(A intersection B)/P(B)

According to given figure only yolanda and Rob are in both club


Therefore,P(A intersection B) =\frac{2}{10}

Number of student in karate club =6

P(B)= \frac{6}{10}

P(A/B) = \frac{2}{10}\div{\frac{6}{10}


Converting division into multiplication by reciprocating the term after division



P(A/B) = \frac{2}{10}\times{\frac{10}{6}



On solving we get ,


P(A/B) = \frac{2}{6}

P(A/B)=\frac{1}{3}


P(A/B) =0.33

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