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kvv77 [185]
2 years ago
13

Given m with arrow = 3 î + 2 ĵ − 5 k and n with arrow = 6 î − 2 ĵ − 4 k, calculate the vector product m with arrow ✕ n with arro

w.
Mathematics
1 answer:
erastovalidia [21]2 years ago
8 0
<span>We know that for two vectors u and v we have that the cross product is equal to : (u2v3 - u3v2) i + (u3v1 - u1v3) j + (u1v2 - u2v1) k Then we have that m x n : ( (2 *-4) - (-5 * -2) ) i + ( (-5*6) - (3 *-4) )j + ( ( 3*-2) - (2*6))k which becomes ( -8 - 10) i + ( -30 + 12) j + ( -6 - 12) k Thus the vector product of m and n is -18 i - 18j -18k</span>
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The result of which expression will best estimate the actual product of (Negative four-fifths) (three-fifths) (Negative StartFra
Natasha_Volkova [10]

Answer:

B or (-1)(1/2)(-1)(1)

Step-by-step explanation:

-4/5 is closest to (-1)

3/5 is closest to 1/2

-6/7 is closest to (-1)

5/6 is closest to 1

hope this helps

7 0
1 year ago
A blimp is 1500 meters high in the air and measures the angles of depression to two stadiums to the west of the blimp. If those
grigory [225]
Let stadium 1 be the one on the left and stadium 2 the one on the right.

Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).

For the next part we need to use the trigonometric function of tangent.

As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)

Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)

Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)

Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)

Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m

Correcting the answer to whole number gives you 1754 m which is the option C.
4 0
2 years ago
Write an equivalent expression for n x a using only addition
bulgar [2K]

Answer:

Equivalent expression for n x a  = a+ a+a+a....n times

Step-by-step explanation:

Given: Expression for n x a .

To find : Write an equivalent expression for n x a using only addition.

Solution : We have given that n x a .

Here, we can say Sum of  a is n times.

We can rewrite it n x a  = a+ a+a+a....n times.

Example : 3 x 2 = 2 +2+ 2.

                   6 = 6 ( true)

Therefore , equivalent expression for n x a  = a+ a+a+a....n times.

7 0
2 years ago
Read 2 more answers
Researchers measured the average blood alcohol concentration C(t) of eight men starting one hour after consumption of 30 mL of e
nekit [7.7K]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data below:

Time, t (hours)__1.0__1.5__2.0__2.5__3.0

C(t) (mg/mL)__0.35_0.26_0.20_0.14_0.09

Average change of C with respect to t over the interval :

(i) [1.0, 2.0] (ii) [1.5, 2.0] (iii) [2.0, 2.5] (iv) [2.0, 3.0]

Average change = ( change in C / change in t) = C2 - C1 / t2 - t1

1) [1.0, 2.0]

C at t = 1 = 0.35 ; C at t = 2 = 0.20

(0.20 - 0.35) / (2 - 1) = - 0.15 / 1 = - 0.15 mg/mL hr

11) [1.5, 2.0]

(0.20 - 0.26) / (2.0 - 1.5) = - 0.06 / 0.5 = - 0.12 mg/mL hr

111) [2.0, 2.5]

(0.14 - 0.20) / (2.5 - 2.0) = - 0.06 / 0.5 = - 0.12mg/mL hr

iv) [2.0, 3.0]

(0.09 - 0.20) / (3.0 - 2.0) = - 0.11 / 1.0 = - 0.11 mg/mL hr

4 0
2 years ago
What is the missing statement in the proof? Scroll down to see the entire proof.
Eva8 [605]

Answer: C. \angle BCA\cong \angle DCB is the missing statement.

Explanation: Given: ΔABC with m∠ABC = 90° (view diagram)

Prove: AB^2 + BC^2 = AC^2

Proof:  1. Draw BD\perp AC (construction)

 2. \angle ABC\cong\angle BDC  (Angles with the same measure are congruent.)

3. \angle BCA\cong \angle DCB (Reflexive Property of Congruence)

4. \triangle ABC\sim \triangle BDC  (AA criterion for similarity)

5. BC:DC=AC:BC  (Corresponding sides of similar triangles are proportional.)

 6.BC^2= AC\times DC  (cross multiplication)----------(1)

7. \angle ABC\cong \angle ADB (Angles with the same measure are congruent)

8. \angle BAC\cong \angle DAB (Reflexive Property of Congruence)

9. \triangle ABC\sim \triangle ADB  (AA criterion for similarity)

10.  AB:AD=AC:AB⇒AB^2=AC.AD --------------(2)

equation (1) + equation (2) ⇒AB^2+BC^2= AC(DC+AD)⇒AB^2+BC^2= AC^2


6 0
1 year ago
Read 2 more answers
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