Ask question

Ask question

All categories

1 year ago

5

A cereal manufacturer decides to offer a new family-sized box based on the regular-sized box. They want the volume of the family

-sized box to be three times the volume of the regular-sized box. However, they want the length of the family-sized box to be the same as the regular-sized box. If they decide to double the width to create the family-sized box, by what factor must they increase the height?

2 answers:

irga5000 [103]1 year ago

8 0

Answer:

Step-by-step explanation:

Given that A cereal manufacturer decides to offer a new family-sized box based on the regular-sized box. They want the volume of the family-sized box to be three times the volume of the regular-sized box. However, they want the length of the family-sized box to be the same as the regular-sized box.

If original dimensions are l,w and h then volume = lwh

Volume of new box is= 3lwh

But here w becomes 2w and l remains the same. Let h' be the new height

Then we have

$l(2w)h' = 3lwh\\h' =1.5 h$

So by 1.5 factor height should be dilated.

Pani-rosa [81]1 year ago

4 0

The answer would be an increase by a factor of 3/2

You might be interested in

Which shows a recursive and an explicit formula for a sequence whose initial term is 14 and whose common difference is −4? A. A(

liberstina [14]

Answer: A. A(1) = 14; A(n) = (n − 1) −4; A(n) = 14 + (n − 1)(−4)

Step-by-step explanation:

Arithmetic sequence is a sequence that is identified by their common difference. Let a be the first term, n be the number of terms and d be the common difference.

For an arithmetic sequence, common difference 'd' is added to the preceding term to get its succeeding term. For example if a is the first term of a sequence, second term will be a+d, third term will give a+d+d and so on to generate sequence of the form,

a, a+d, a+3d, a+4d...

Notice that each new term keep increasing by a common difference 'd'

The nth term of the sequence Tn will therefore give Tn = a+(n-1)d

If the initial (first) term is 14 and common difference is -4, the nth of the sequence will be gotten by substituting a = 14 and d = -4 in the general formula to give;

Tn = 14+(n-1)-4 (which gives the required answer)

Tn = 14-4n+4

Tn = 18-4n

5 0

2 years ago

Read 2 more answers

Farmer gray has 30 flower pots he plants 10 seeds in each pot how many seeds does he plant?

Keith_Richards [23]

30 flower pots times 10 seeds in each equals 300 seeds

5 0

2 years ago

Read 2 more answers

If h:k = 2:5, x:y=3:4 and 2h+x:k+2y = 1:2, find the ratio h-x: k-y.

fenix001 [56]

Given:

$h:k=2:5,x:y=3:4,2h+x:k+2y=1:2$

To find:

$h-x:k-y$

Solution:

We have, $h:k=2:5$ and $x:y=3:4$ .

Let the values of h and k are 2a and 5a respectively.

Let the values of x and y are 3b and 4b respectively.

We have,

$2h+x:k+2y=1:2$

It can be written as

$\dfrac{2h+x}{k+2y}=\dfrac{1}{2}$

$\dfrac{2(2a)+(3b)}{5a+2(4b)}=\dfrac{1}{2}$

$\dfrac{4a+3b}{5a+8b}=\dfrac{1}{2}$

$2(4a+3b)=1(5a+8b)$

On further simplification, we get

$8a+6b=5a+8b$

$8a-5a=8b-6b$

$3a=2b$

$a=\dfrac{2b}{3}$

Now,

$h-x:k-y=\dfrac{h-x}{k-y}$

$h-x:k-y=\dfrac{2-3b}{5a-4b}$

$h-x:k-y=\dfrac{2\times \dfrac{2b}{3}-3b}{5\times \dfrac{2b}{3}-4b}$

$h-x:k-y=\dfrac{\dfrac{4b}{3}-3b}{\dfrac{10b}{3}-4b}$

On further simplification, we get

$h-x:k-y=\dfrac{\dfrac{4b-9b}{3}}{\dfrac{10b-12b}{3}}$

$h-x:k-y=\dfrac{-5b}{-2b}$

$h-x:k-y=\dfrac{5}{2}$

$h-x:k-y=5:2$

Therefore, the ratio $h-x:k-y$ is $5:2$ .

8 0

1 year ago

Abby has a collection of 61 dimes and nickels worth $4.40. How many nickels does she have? answer

timofeeve [1]

Answer:88 nickels

Step-by-step explanation:

3 0

2 years ago

In a certain country, a letter up to 1 ounce requires postage in the amount of $0.42, and each additional ounce (or fraction of

KIM [24]

Answer:

Is there any multiple choice answers?

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers