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2 years ago

Name the corresponding part if RST WXY. ST = A) WY B) WX C) XY

2 answers:

7 0

To determine the part of the triangle that corresponds to the parts of the other triangle, we can just see how they are arranged in the equation,
RST = WXY
The corresponding side of side ST is equal to side XY. Thus, the answer is letter C.

ELEN [110]2 years ago

7 0

Answer:

Option C

Step-by-step explanation:

we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal and their corresponding angles also are equal

In this problem

$\frac{RS}{WX}=\frac{ST}{XY}=\frac{RT}{WY}$

therefore

the corresponding sides are

RS and WX

ST and XY

RT and WY

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Determine the solution set of x^2-80=0.

Stella [2.4K]

X^2 - 80 = 0
x^2 = 80 ...take the square root of both sides, eliminating the ^2
x = (+-) sqrt 80
x = (+-) sqrt 16 * 5
x = (+-) 4 sqrt 5

so x = 4 sqrt 5 or x = -4 sqrt 5

6 0

2 years ago

Read 2 more answers

Customers are used to evaluate a preliminary product design. In the past, 95% of highly successful products received good review

Sever21 [200]

Answer:

a. 61.5%; b. About 61.8%; c. About 36.4%

Step-by-step explanation:

This is a kind of question that we can solve using the Bayes' Theorem. We have here all the different conditional probabilities we need to solve this problem.

According to that theorem, the probability of a selected product attains a good review is:

$\\ P(G) = P(G|H)*P(H) + P(G|M)*P(M) + P(G|P)*P(P)$ (1)

In words, the probability that a selected product attains a <em>good review</em> is an <em>event </em>that depends upon the sum of the conditional probabilities that the product comes from <em>high successful product</em> P(G|H) by the probability that this product is a <em>highly successful product</em> P(H), plus the same about the rest of the probabilities, that is, P(G|M)*P(M) or the probability that the product has a good review coming from a <em>moderately successful</em> product by the probability of being moderately successful, and a good review coming from a poor successful product by the probability of being poor successful or P(G|P)*P(P).

<h3>The probability that a randomly selected product attains a good review</h3>

In this way, the probability that a randomly selected product attains a good review is the result of the formula (1). Where (from the question):

P(G|H) = 95% or 0.95 (probability of receiving a good review being a highly successful product)

P(G|M) = 60% or 0.60 (probability of receiving a good review being a moderately successful product)

P(G|P) = 10% or 0.10 (probability of receiving a good review being a poorly successful product)

P(H) = 40% or 0.40 (probability of being a highly successful product).

P(M) = 35% or 0.35 (probability of being a moderately successful product).

P(P) = 25% or 0.25 (probability of being a poor successful product).

Then,

$\\ P(G) = P(G|H)*P(H) + P(G|M)*P(M) + P(G|P)*P(P)$

$\\ P(G) = 0.95*0.40 + 0.60*0.35 + 0.10*0.25$

$\\ P(G) = 0.615\;or\; 61.5\%$

That is, <em>the probability that a randomly selected product attains a good review</em> is 61.5%.

<h3>The probability that a new product attains a good review is a highly successful product</h3>

We are looking here for P(H|G). We can express this probability mathematically as follows (another conditional probability):

$\\ P(H|G) = \frac{P(G|H)*P(H)}{P(G)}$

We can notice that the probability represents a fraction from the probability P(G) already calculated. Then,

$\\ P(H|G) = \frac{0.95*0.40}{0.615}$

$\\ P(H|G) =\frac{0.38}{0.615}$

$\\ P(H|G) =0.618$

Then, the probability of a product that attains a good review is indeed a highly successful product is about 0.618 or 61.8%.

<h3>The probability that a product that <em>does not attain </em>a good review is a moderately successful product</h3>

The probability that a product does not attain a good review is given by a similar formula than (1). However, this probability is the complement of P(G). Mathematically:

$\\ P(NG) = P(NG|H)*P(H) + P(NG|M)*P(M) + P(NG|P)*P(P)$

P(NG|H) = 1 - P(G|H) = 1 - 0.95 = 0.05

P(NG|M) = 1 - P(G|M) = 1 - 0.60 = 0.40

P(NG|P) = 1 - P(G|M) = 1 - 0.10 = 0.90

$\\ P(NG) = 0.05*0.40 + 0.40*0.35 + 0.90*0.25$

$\\ P(NG) = 0.385\;or\; 38.5\%$

Which is equal to

P(NG) = 1 - P(G) = 1 - 0.615 = 0.385

Well, having all this information at hand:

$\\ P(M|NG) = \frac{P(NG|M)*P(M)}{P(NG)}$

$\\ P(M|NG) = \frac{0.40*0.35}{0.385}$

$\\ P(M|NG) = \frac{0.14}{0.385}$

$\\ P(M|NG) = 0.363636... \approx 0.364$

Then, the <em>probability that a new product does not attain a good review and it is a moderately successful product is about </em>0.364 or 36.4%.

8 0

1 year ago

(30 points) The coordinates of the vertices of quadrilateral JKLM are J(−3, 2) , K(3, 5) , L(9, −1) , and M(2, −3) .

Tpy6a [65]

(30 points) The coordinates of the vertices of quadrilateral JKLM are J(−3, 2) , K(3, 5) , L(9, −1) , and M(2, −3) .
Which statement correctly describes whether quadrilateral JKLM is a rhombus?

Quadrilateral JKLM is not a rhombus because there is only one pair of opposite sides that are parallel.

6 0

2 years ago

Read 2 more answers

A small coffee shop sells freshly squeezed juices in a refrigerated unit with slots where juice is displayed. These slots are ca

lianna [129]

Answer: kindly check attached picture

Step-by-step explanation:

Given the data below :

Juice Mango Orange Apple Pineapple Grapefruit Grape

Proportion of Facings 0.1875 0.250 0.250 0.125 0.125 0.0625

In other to make the proportion of facing visible on the graph we multiply by 100; Hence,

Juice Mango Orange Apple Pineapple Grapefruit Grape

Proportion of Facings 18.75 2.50 2.50 1.25 1.25 6.25

Juice Mango Orange Apple Pineapple Grapefruit Grape

Observed Number of Sales 23 35 46 12 10 5

(a) Construct a single bar chart that contains both the expected proportion of sales based on the proportion of facings and the observed proportion of sales for each type of juice.

Using an online bar chart plotter, the proportion of facings by the blue bars and the red bars depicts the observalues for different type of juice Given.

Hence, from the plot, it could be clearly seen that the distribution of facing is different or not equal to the number of juice sold.

The barchart produced is attached below.

8 0

2 years ago

High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa

Misha Larkins [42]

Answer:

<u>The correct answer is that a student have to score 1.41 standard deviations above the mean to be publicly recognized.</u>

Step-by-step explanation:

For answering the question, we don't know the score mean of the National Financial Capability Challenge Exam and neither the population or number of students who take the exam. The only information provided is that the public recognition in this normal distribution is only for students that scores in the top 8%. In other words for students above 92% of the population.

With this information, we can go to a Z Score Table and check that for being on the top 8% (above the 92% of any population), your result must be 1.405 standard deviations above the mean.

<u>Rounding the answer to 2 decimal places, it's 1.41 standard deviations above the mean.</u>

7 0

2 years ago