Given the data 29.65 28.55 28.65 30.15 29.35 29.75 29.25 30.65 28.15 29.85 29.05 30.25 30.85 28.75 29.65 30.45 29.15 30.45 33.65
1 answer:
You might be interested in
Answer:
The price for each kilogram of strawberries is $7.50
Step-by-step explanation:
<u><em>The question is</em></u>
Blues berry farm charges Percy a total of $24.75 for entrance and 2.5 kilograms of strawberries. The entrance fee is $6 and the price for each kilogram of strawberries is constant
Determine the price for each kilogram of strawberries
Let
x ----> the price for each kilogram of strawberries
we know that
The entrance fee plus the price of each kilogram of strawberries multiplied by the number of kilogram of strawberries must be equal to $24.75
so
The linear equation that represent this situation is
solve for x
subtract 6 both sides
divide by 2.5 both sides
therefore
The price for each kilogram of strawberries is $7.50
Answer:
(a1) The probability that temperature increase will be less than 20°C is 0.667.
(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.
(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.
(c) The expected value of the temperature increase is 17.5°C.
Step-by-step explanation:
Let <em>X</em> = temperature increase.
The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].
The probability density function of <em>X</em> is:
(a1)
Compute the probability that temperature increase will be less than 20°C as follows:
Thus, the probability that temperature increase will be less than 20°C is 0.667.
(a2)
Compute the probability that temperature increase will be between 20°C and 22°C as follows:
Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.
(b)
Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:
Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.
(c)
Compute the expected value of the uniform random variable <em>X</em> as follows:
Thus, the expected value of the temperature increase is 17.5°C.