Eliot needs to replace a window that is in the shape of a semicircle.

In your internship with Lewis, Lee, & Taylor Inc. you have been asked to forecast the firm's additional funds needed (AFN) f

Allushta [10]

Answer:

Option B. -$22,000

Step-by-step explanation:

Last year data :

Sales = $200,000

Profit margin = 20%

Total assets = $120,000

Accounts payable = $50,000

Accruals = $20,000

Sales growth rate = 40%

Calculate total increase in total assets :

Increase in total assets = Total assets × Growth rate

= 120,000 × 40%

= $48,000

Calculate increase in spontaneous liabilities :

Increase in spontaneous liabilities = (50,000 + 20,000) × 40%

= $28,000

Calculate increase in retained dividend :

calculate the increase sales :

increased sales = 200,000 × (1 + 0.40)

= 280,000

calculate profit margin for next year on increase sales :

Profit margin on increased sales = 280,000 × 20%

= $56,000

Calculate retained earning :

Retained earning = profit - payout of profit

= 56,000 - ( 56,000 × 25% )

= 56,000 - 14,000

= $42,000

Calculate AFN :

AFN = Increase in assets - Increase in liabilities - increase in retained earning

= 48,000 - 28,000 - 42,000

= -$22,000

Option B. is the answer.

6 0

2 years ago

A mountain climber took 2 minutes to rappel down 60 feet. Which equation shows the correct calculation to show his movement per

Gelneren [198K]

Answer: C

Step-by-step explanation: going down would mean it's negative, so -60, and you're comparing the feet by the amount of minutes so dividing it by 2 which would be -30. so the answer would be c, -60/2=-30

8 0

1 year ago

Read 2 more answers

Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1

irina [24]

$\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)
\end{cases}\\\\
-------------------------------\\\\
\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}$

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)