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denpristay [2]
2 years ago
9

Sabas dance class is 3 miles from her home. Her music class is 12 miles from her home. Write an equation that shows the number o

f times farther sabas music class is from her home than her dance class is from her home
Mathematics
1 answer:
Alenkasestr [34]2 years ago
5 0

Answer:

3x = 12

x = 4

Step-by-step explanation:

The equation shows that the dance class is three times away from her house, and when you multiply that value by "x" you are solving for the amount of times more the value of "3" is from 12. Therefore, the distance from the dance class is four times farther from her music class if you evaluate the expression.

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Jay stores hay in cubic stacks on his farm. If the length of each stack is 2/3 yards, what is the volume of hay in each stack? 1
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\left( \dfrac{2}{3}\,yd\right)^{3}=\dfrac{8}{27}\,yd^{3}

The 4th selection is appropriate.
3 0
2 years ago
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The local theatre production company sells advance tickets (a) for $16 per seat. On the night of the performance, tickets (t) ar
Musya8 [376]

Answer:

16a + 22t = 11826

Step-by-step explanation:

Cost of 1 (a) ticket = $16

Cost of 1 (t) ticket = $22

Total tickets sold = 648

Cost of 648 tickets = $11826

So eqn will be => 16a + 22t = 11826

6 0
2 years ago
If f(x)=x2+10sinx, show that there is a number c such that f(c)=1000.
gayaneshka [121]
F(x) is continuous for all x.

Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.

At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.

Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0

Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
7 0
2 years ago
The closing price (in dollars) per share of stock of tempco electronics on the tth day it was traded is approximated by p(t) = 2
Vaselesa [24]

solution:

The closing price (in dollars) per share of stock of Tempco Electronics on the tth day it was  

traded is approximated by  

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15 (0 ≤ t ≤ 24)  

where t = 0 corresponds to the time the stock was first listed on a major stock exchange.  

What was the rate of change of the stock's price at the close of the 15th day of trading?  

P'(t) = 12(cos πt/30) - 6 (cos πt/15) + 4(cos πt/10) - 3(cos 2πt/15)  

t = 15  

P'(t) = 12(cos 15π/30) - 6 (cos 15π/15) + 4(cos 15π/10) - 3(cos 30π/15)  

P'(t) = 12(cos π/2) - 6 (cos π) + 4(cos 3π/2) - 3(cos 2π)  

P'(t) = 12(0) - 6(-1) + 4(0) - 3(1) = 6 - 3  

P'(t) = $3 per day RATE OF CHANGE  

the closing price on that day

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15  

t = 15  

P(t) = 20 + 12 sin 15π/30 − 6 sin 15π/15 + 4 sin 15π/10 − 3 sin 30πt/15  

P(t) = 20 + 12 sin π/2 − 6 sin π + 4 sin 3π/2 − 3 sin 2π  

P(t) = 20 + 12(1) − 6(0) + 4(-1) − 3(0) = 20 + 12 - 0 - 4 - 0 = 20 + 12 - 4  

P(t) = $28 per share close price



4 0
2 years ago
Use technology or a z-distribution table to find the indicated area.
KengaRu [80]

Answer:

I think it's answer D. (141).  :D

Step-by-step explanation:

6 0
2 years ago
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