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tekilochka [14]
2 years ago
14

A bicycle wheel is 63 centimeters from top to bottom. When the wheel goes all the way around one time,the bicycle travels 198 ce

ntimeters. How can this information be used to estimate the value of
Mathematics
1 answer:
OlgaM077 [116]2 years ago
8 0

Answer:

π = 198/63

Divide the distance traveled by the wheel to guess the value or estimate the value of π.

Step-by-step explanation:

Height of the wheel: Diameter of the circle

Perimeter of the circle = π*diameter of the circle

Divide the diameter of the circle by the perimeter of the circle.

π = 198/63

<em><u>Hope this helps.</u></em>

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1 year ago
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If quadrilateral PQRS is a rectangle, then which of the following is true?
brilliants [131]

∠STP ≅ ∠QTR is the True statement ⇒ answer C

Step-by-step explanation:

In any rectangle

1. Each two opposite sides are equal and parallel

2. The measure of its vertex angles is 90°

3. The two diagonals are equal

Now lets find the true statements

∵ PQRS is a rectangle

∴ PS = QR ⇒ opposite sides

∴ PQ = SR ⇒ opposite sides

∴ PR = QS ⇒ diagonals

A.  ∠PSQ ≅ ∠QSR

∵ The diagonals of the rectangle do not bisect the vertex angles

∴ AQ does not bisect angle S

∴  m∠PSQ ≠ m∠QSR

∴  ∠PSQ not congruent ∠QSR

∠PSQ ≅ ∠QSR ⇒ False

B. segment SR ≅ segment RQ

∵ SR and RQ are two adjacent sides

∵ The adjacent side in the rectangle not equal

∴ SR ≠ QR

∴ segment SR not congruent to segment RQ

segment SR ≅ segment RQ ⇒ False

C. ∠STP ≅ ∠QTR

∵ PR intersects QS at point T

∴ m∠STP = m∠QTR ⇒ vertically opposite angles

∴ ∠STP ≅ ∠QTR

∠STP ≅ ∠QTR ⇒ True

D. segment PS ≅ segment PR

∵ PS is a side in the rectangle

∵ PR is a diagonal in the rectangle

∵ The side of the rectangle not equal the diagonal of the rectangle

∴ PS ≠ PR

∴ segment PS not congruent to segment PR

segment PS ≅ segment PR ⇒ False

∠STP ≅ ∠QTR is the True statement

Learn more:

You can learn more about rectangle in brainly.com/question/6594923

#LearnwithBrainly

8 0
2 years ago
Read 2 more answers
Tim and Jim are working on a school project together. If he had to work by himself, it would take
Vladimir [108]

Answer: 6 hours

Step-by-step explanation:

Given, Tim and Jim are working on a school project together.

Tim takes 10 hours to complete the school project.

If Jim worked alone, it would take him 15 hours

Let t be the time they both take if they work together.

Then, \dfrac{1}{t}=\dfrac{1}{\text{Time taken by Tim}}+\dfrac{1}{\text{Time taken by jim}}

\Rightarrow\ \dfrac{1}{t}=\dfrac{1}{10}+\dfrac{1}{15}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{3+2}{30}=\dfrac{5}{30}\\\\\Rightarrow\dfrac{1}{t}=\dfrac{1}{6}\\\\\Rightarrow t=6

So, it will take<u> 6 hours</u> to complete the school project together .

4 0
1 year ago
The graphs of the function f (given in blue) and g (given in red) are plotted above. Suppose that u(x)=f(x)g(x) and v(x)=f(x)/g(
prisoha [69]
I included the graphs of the functions f(x) (given in blue) and g(x) (given in red) in the attached pdf file.

The questions are:

1) Find u(1) and
2) Find v(1)

Solutions:

1) u(x) = f(x) g(x) => u(1) = f(1) * g(1)

From the graphs f(1) = 1 and g(1) = 2, then f(1)*g(1) = 1*2 =2

Answer: 2

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Answer: 0.5
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The assumptions made are: The gas molecules from Caesar's last breath are now evenly dispersed in the atmosphere. The atmosphere
Dovator [93]

Answer:

2.6\times 10^{19}m^{3}

Step-by-step explanation:

we have given thickness of atmosphere =50 km

radius of earth =6400 km

average temperature of atmosphere=15°C

Average pressure of atmosphere= 0.20 atm

we have to calculate the volume of atmosphere

so the we have to calculate the volume of atmosphere = ( volume of earth +atmosphere) - volume of earth

volume of atmosphere =\frac{4}{3}\times\pi \times \left ( 6400+50 \right )^{3}-\frac{4}{3}\times \pi\times 6400^3

=2.6\times 10^{19}m^{3}

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