Solution: We are given:
Total students = 10 + 30 + 10 =50
Number of students who received A grade = 3 + 10 + 5 = 18
Number of senior student's who received A grade is = 10
Let A be the event that the student is senior and B be the event that he or she earned an A. Then,


Now the probability a student chosen at random from this class and is found to have earned an A, the probability that he or she is a senior is:



We know, acceleration = change in speed / time
a = (3.5 - 3.1) / 15
a = 0.4 / 15
a = 0.026 m/s²
In short, Your Answer would be: 0.026 m/s²
Hope this helps!
Answer:

Step-by-step explanation:
The picture of the question in the attached figure
step 1
Find the value of x
Let
O ----> the center of the circle
we know that
Triangle BOC≅Triangle COD
----> by central angle
----> by central angle

therefore

substitute the given values

solve for x

step 2
Find the measure of angle BAD
we know that
The inscribed angle is half that of the arc it comprises.
so
![m\angle BAD=\frac{1}{2} [arc\ BC+arc\ CD]](https://tex.z-dn.net/?f=m%5Cangle%20BAD%3D%5Cfrac%7B1%7D%7B2%7D%20%5Barc%5C%20BC%2Barc%5C%20CD%5D)


substitute
![m\angle BAD=\frac{1}{2} [73^o+73^o]=73^o](https://tex.z-dn.net/?f=m%5Cangle%20BAD%3D%5Cfrac%7B1%7D%7B2%7D%20%5B73%5Eo%2B73%5Eo%5D%3D73%5Eo)
base 16y^2
height y^2 + y + 3
V = b*h
V = 16y^2(y^2 + y + 3)
V = 16y^4 + 16y^3 + 48y^2
Last option
96 messages .... $4.80
155 messages .... x
x= (155x4.80):96=7.75