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Natali [406]
2 years ago
8

Carolyn has $2.55 in her purse in nickels and dimes. The number of nickels is nine less than three times the number of dimes. Fi

nd the number of each type of coin.
Mathematics
1 answer:
Flauer [41]2 years ago
5 0

Hi, the answer is ;

Answer:

12 dimes and 27 nickels

Step-by-step explanation:

.05N + .1d = 2.55

N= 3d - 9

0.05 (3d-9) + 0.1d = 2.55

0.15d - 0.45 + 0.1d = 2.55

0.25d = 2.55 + 0.45

0.25d = 3

D = 12

N = 3 (12) - 9

N = 36 - 9

N = 27

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Jennifer can run 12 miles in 2 hours, and she can bike 33 miles in 3 hours. What is Jennifer’s biking speed?
anastassius [24]

Answer:

11 miles per hour

Step-by-step explanation:

The biking speed is found by taking the miles and dividing by the hours

33 miles/ 3 hours

11 miles per hour

3 0
2 years ago
2. ½ of a group of chickens tried to cross the road. Only ¾ of those chickens made it to the other side. What fraction of the or
ArbitrLikvidat [17]
Let me help you visualize this one.

Let's say we have 12 chickens.

OOOOOOOOOOOO

We divide this group in half (1/2 who tried to cross the road.)

OOOOOO

And here, we need to get 3/4 of the 6 left.

3/4 can be represented as 0.75 of 1.

6 times 0.75 equals to 4.5.

OOOOC (Woah, that chicken is split in half!)

What fraction is 4.5 of the original amount?

Well, that's for you to find out! Good luck in solving this question.
3 0
1 year ago
Read 2 more answers
A manager wants to build 3-sigma x-bar control limits for a process. The target value for the mean of the process is 10 units, a
lubasha [3.4K]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Mean = 10

Sample size = 9

Standard deviation = 6

We need to find the upper and lower control limits.

so, Lower limit would be

\bar{x}-3\dfrac{\sigma}{\sqrt{n}}\\\\=10-3\times \dfrac{6}{\sqrt{9}}\\\\=10-6\\\\=4

Upper limit would be

\bar{x}+3\dfrac{\sigma}{\sqrt{n}}\\\\=10+3\times \dfrac{6}{\sqrt{9}}\\\\=10+6\\\\=16

Hence, Third option is correct.

3 0
2 years ago
The height of seaweed of all plants in a body of water are normally distributed with a mean of 10 cm and a standard deviation of
Degger [83]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: height of seaweed.

X~N(μ;σ²)

μ= 10 cm

σ= 2 cm

You have to find the value of the variable X that separates the bottom 0.30 of the distribution from the top 0.70

P(X≤x)= 0.30

P(X≥x)= 0.70

Using the standard normal distribution you have to find the value of Z that separates the bottom 0.30 from the top 0.70 and then using the formula Z= (X-μ)/σ translate the Z value to the corresponding X value.

P(Z≤z)= 0.30

In the body of the table look for the probability of 0.30 and reach the margins to form the Z value. The mean of the distribution is "0" so below 50% of the distribution you'll find negative values.

z= -0.52

Now you have to clear the value of X:

Z= (X-μ)/σ

Z*σ= X-μ

X= (Z*σ)+μ

X= (-0.52*2)+10= 8.96

The value of seaweed height that divides the bottom 30%  from the top 70% is 8.96 cm

I hope this helps!

7 0
2 years ago
Figures R, S, and T are all scaled copies of one another. Figure S is a scaled copy of R using a scale factor of 3. Figure T is
MakcuM [25]

<em><u>Answer:</u></em>

1/2

1/3

6

1/6

<em><u>Step-by-step explanation:</u></em>

When we are finding the opposite of a scale factor, the scale factor is always the reciprocal. E.g. From S to R, the scale factor is 3, so from R to S, the scale factor is 1/3 so:

1. From T to S, it's the reciprocal of the scale factor (2) so 1/2

2. From S to R, it's the reciprocal of the scale factor (3) so 1/3

3. From R to T, is the from a figure to a figure to a figure so we can multiply the two scale factors (2 and 3) to get 6

4. From T to R, that's the opposite of R to T, so it's the reciprocal of the scale factor from R to T (6) so 1/6

4 0
2 years ago
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