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2 years ago

The selling price of a box of crackers is $1.75 You mark the crackers up to $2.54 . What is the markup percentage?

Mathematics

2 answers:

Aleks04 [339]2 years ago

8 0

The markup percentage is 45.14%

Step-by-step explanation:

The given is:

The selling price of a box of crackers is $1.75
You mark the crackers up to $2.54

We need to find the markup percentage

The markup percentage = $\frac{New-Old}{old}$ × 100%

∵ The selling price of a box of crackers is $1.75

∴ Old = 1.75

∵ You mark the crackers up to $2.54

∴ New = 2.54

- Substitute these values in the rule above

∵ The markup percentage = $\frac{2.54-1.75}{1.75}$ × 100%

∴ The markup percentage = $\frac{0.79}{1.75}$ × 100%

∴ The markup percentage = 0.4514 × 100%

∴ The markup percentage = 45.14%

The markup percentage is 45.14%

Learn more:

You can learn more about percentage in brainly.com/question/1834017

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stepan [7]2 years ago

8 0

Answer:

The markup percentage is 45%.

Step-by-step explanation:

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2 years ago

A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft, and it weighs 50 lbs. T

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Answer:

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Step-by-step explanation:

Product 1 has a unit volume of 10 cu ft

Product 2 has a unit volume of 3 cu ft

The truck has 2300 cu ft of space

Product 1 weighs 50 lbs

Product 2 weighs 40 lbs

The truck can carry 21000 lbs

Let X be the units of product 1

Let Y be the units of product 2

The given information can be expressed as:

10X+3Y=2300...(1)

50X+40Y=21000...(2)

Solving the system of equations:

10X+3Y=2300...(1)

10X=2300-3Y

X=(2300-3Y)/10

Substituting X in (2) we have:

50X+40Y=21000

50[(2300-3Y)/10]+40Y=21000

50[(2300/10)-(3Y/10)]+40Y=21000

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11500-15Y+40Y=21000

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25Y=9500

Y=380

Substituting Y in (1) we have:

10X+3Y=2300...(1)

10X+3(380)=2300

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10X=2300-1140

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So 116 units of the first product and 380 units of the second product can be transported in a single shipment with one truck.

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2 years ago