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soldier1979 [14.2K]
1 year ago
10

What is the maximum number of times two planes can intersect? What is the minimum number of times they can intersect?

Mathematics
1 answer:
nordsb [41]1 year ago
8 0
The minimum number of times two planes can intersect is zero, because if the planes are parallel to each other, they will never intersect. we can take the example of floor and roof, both are parallel to each other and no intersection. If the two planes are in same plane the maximum number of times they can intersect is infinite for example if we consider a line we can intersect at infinite points.
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A park has a 333 meter (\text{m})(m)left parenthesis, start text, m, end text, right parenthesis tall tether ball pole and a 6.8
dybincka [34]

Answer:option B & D are correct

Step-by-step explanation:

Given options are  

                                             A              B          C             D           E        

Tether ball pole shadow      1.35         1.8        3.75        0.6       2

Flagpole shadow                  3.4          4.08      8.35       1.36      4.8

Ratio of corresponding height & shadows  should be same

3 meter tall tether ball pole and a 6.8 tall flagpole

=> Ratio  = 6.8/3    = 68/30  = 34/15  

A    - 3.4/1.35 =   340/135     ≠ 34/15( 306/135)

B  -  4.08/1.8  = 408/180   =  34/15  = 34/15  ( Correct option)

C    8.35/3.75  = 835/375  =  167/75   ≠ 34/15( 170/75)

D  1.36/0.6  = 136/60   =  34/15  = 34/15   ( Correct option)

E  4.8/2  = 48/20   =  12/5   = 36/15    ≠ 34/15

option B & D are correct

6 0
1 year ago
Read 2 more answers
Jody bought 20 shares of amazon at the close price of $121.00. She bought 20 more shares a year later at the price of $127.00. T
hjlf

Answer:

Jody made $210 after all of these transactions.

Step-by-step explanation:

Jody bought 20 shares of amazon at the price of $121.00

= 121.00 × 20 = $2,420

After one year she bought 20 more shares at the price of $127.00

= 127.00 × 20 = $2,540

Her broker charges $50.00 for each transaction = 50 × 2 = $100

Total cost of all shares = 2,420 + 2,540 + 100 = $5,060

She sold all of her shares at the price of $133.00

= 133 × 40 = $5,320

She gave broker charge for this transaction = $50.00

Total selling amount  = 5,320 - 50 = $5,270

Profit = Selling amount - cost

Profit = 5,270 - 5,060 = $210

Jody made $210 after all of these transactions.

8 0
1 year ago
Read 2 more answers
Washington is 44 miles south of Lawrence. and midland is 63 miles east of Lawrence. how far apart are Washington and midland?
gregori [183]
The answer is 21 miles
3 0
1 year ago
Hello, I was wondering if someone would be able to help me with this problem I'm on. Thanks :)
koban [17]

<span><span>Price after trade discount = $14,000 - (40% trade discount)

Price after trade discount = $14,000 - ($14,000 * 0.4)

Price after trade discount = $14,000 - ($5,600)

Price after trade discount = $8,400 </span>Price after trade discount = $8,400

2/10 EOM price = $8,400 - (2% discount)

2/10 EOM price = $8,400 - ($8,400 * 0.02)

2/10 EOM price = $8,400 - ($168)

2/10 EOM price = $8,232

So Intel will pay $8,232 on August 5.
Hope this helps.
</span>
4 0
1 year ago
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
1 year ago
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